preg replace and OR

[digitalecartoons]

So how does that work exactly with preg_replace? Is there some kind of order? Lets take part of this text as string:

 

"occurrence of \r\n into TWO line break"

 

so when using: $message = preg_replace('~\r\n|\r|\n~', "\r\n", $message); to turn things into proper \r\n newline codes

 

it first searches for \r\n, making it \r\n so it would remain:

"occurrence of \r\n into TWO line break"

 

then it would replace \r for \r\n, making it

"occurrence of \r\n\n into TWO line break"

 

finally it would replace \n for \r\n making it

"occurrence of \r\r\n\r\n into TWO line break"

 

Thats the way I see it , but it probably doesn't work that way with preg_replace and those 3 options seperated by an OR character?

[btherl]

regexps don't replace things that are already replaced.  So the answer is no.

[digitalecartoons]

But so it first searches for the 1st part \r\n then for the 2nd and finaly 3rd? I mean when there are 3 OR options a|b|c it first does a, then b, then c in that order?

[btherl]

Yes it does.  Try it and you'll see