[SOLVED] include "page1.php" if cant find "page2.php"

[farkewie]

Hi im trying to trap errors in my include statments here is y code but it is not working.

 

 

<?php 	     

if (isset($page)){

	include ("$dir/$page.php");

	if (!include("$dir/$page.php")) {

		include ("$dir/main.php");
	}
}
else {

	include ("$dir/main.php");
}
?>

[rajivgonsalves]

here you go

 

<?php    

if (isset($page) && file_exists("$dir/$page.php")) {

include ("$dir/$page.php");

}

else

{

include ("$dir/main.php");

}

?>

[Prismatic]

edit: ^^ works same with less code 

 

file_exists() is what you want

 

<?php 	     
if(isset($page))
{
if(file_exists($dir ."/". $page .".php"))
{
	include ($dir ."/". $page .".php");
}
else
{
	include($dir."/main.php");
}
}
else
{
include ($dir."/main.php");
}
?>

[farkewie]

Thank you so much it works perfectly.