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[SOLVED] NEED code that will check the time the user spends on the webpage.

andz

By andz
in PHP Coding Help

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Mr P!nk Member

Mr P!nk

Posted
Posted

Place the following script between the <HEAD> and </HEAD> tags:


<script language="javascript">
<!-- begin

function TimedPop() {
url = "URL/to/popup.html";
width = 320; // width of window in pixels
height = 390; // height of window in pixels
delay = 60; // time in seconds before popup opens
timer = setTimeout("popup(url, width, height)", delay*1000);
}

// end -->
</script>

Add the following code into your <BODY> tag:

onLoad="TimedPop()"

Your <BODY> tag should then look something like this:

<BODY onload="TimedPop()" bgcolor="#ffffff" text"#000000">

 

this was found in a matter of seconds using google search,http://www.nowsell.com/pop-ups/pop-up-scripts.html

 

hope it helps

 

Mr P!nk Member

Mr P!nk

Posted
Posted

i just tried this and it worked for me

 

<script language="javascript">
<!-- begin

function TimedPop() {
url = "http://yoursite.co.uk/popup/wherever.html";
width = 320; // width of window in pixels
height = 390; // height of window in pixels
delay = 5; // time in seconds before popup opens
timer = setTimeout("window.open(url, width, height)", delay*1000);
}

// end -->
</script>

</head>

<BODY onload="TimedPop()" bgcolor="#ffffff" text"#000000">


some text or other 

</body>

andz Member

andz

Posted
  • Author
Posted

is there a way that this script will only work if the user is not login? so if the user is already logged in, this script will not be activated, if the user is not login, the popup script will activate.

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