$i remains the same in preg_match_all

[Michan]

Hi,

 

I'm having a problem updating the $i from 0 to 1 in this code. For some reason, $i remains the same throughout the loop, Could somebody please tell me what's going wrong?

 

The code functions; I've tested it and the $i remains 0 (or 1, whatever is given) constantly.

 

$text = '[image=1234]Caption 1![/image]Blah blah[image=4321]Caption 2.[/image]';

$pattern = "#\[image=(.*?)\]#si";
preg_match_all($pattern,$text,$matches, PREG_SET_ORDER);

for ($i = 0; $i < sizeof($matches); $i++) {

    $sql = mysql_query("SELECT file FROM vg_files WHERE id=".$matches[$i][1]);
$row = mysql_fetch_array($sql);

$pattern_find = "#\[image=(.*?)\](.*?)\[\/image\]#si";
$pattern_replace = ''.$row['file']."<BR>$2";
$text = preg_replace($pattern_find,$pattern_replace,$text);

}

 

Thanks in advance.

[Michan]

Sorry to bump, but.. anybody?

[CraigSherwood]

Michan,

see my post in the Help forum. Got an issue very similar to yours which may help. Mine is so close to being solved its almost painful.

Just can't quite figure out the last bit - maybe you can? Even if you can't it may help in some way.

The post is listed under CraigSherwood.