Regexp madness...

[dittonamed]

Say I've got this text "0.0113", or "30.6013", or "5.7794"

 

And I want to find the ONE with the 9 in the third place right of the decimal place, (easy enough) 

 

THEN...  :-\

 

Replace the

        1. third character right of the decimal place with a 1

        2. fourth character right of the decimal place with a 7

        3. fifth character right of the decimal place with a 5

            ... Without changing any other characters

 

Example:

$haystack = array(0.0113, 30.6013, 5.7794);

foreach ($haystack as $h) {

    if (preg_match('/\...9/i', $h)) { #Found the right one

        #Now how to replace only those chars in those positions? ???

    }

}

 

Anyone out there be such a master?! Y'ahar har

 

Thanks,

Ben

[Lumio]

I don't know for what you could need that... but:

<?php
$haystack = array(0.0113, 30.6013, 5.7794);
foreach ($haystack as $i => $h) {
if (preg_match('/^([\d]+\.)([\d][\d])(9[\d]*)$/', $h, $match)) {
	/*
		the regex means: one or more digit followd by . followed by 2 single digits followed by 9
		followed by 0 or more digits and that all should begin from the first sign and ends to the
		last sign.
	*/
	$_h = $match[0]; //get all, that got found
	if (isset($match[3])) { //if the nine exists - do it!
		$_tmp = '175'.substr($match[3], 3);
		$_tmp = substr($_tmp, 0, strlen($match[3])); //remove to many signs... we only want the length we got
		//so if we only has 94 it won't get 175 but 17
		$_h = $match[1].$match[2].$_tmp;
	}

	$haystack[$i] = $_h; //put it back into the array
    }
}

echo '<pre>'.print_r($haystack,true).'</pre>';
?>