[SOLVED] Using a Function in preg_replace

[marcus]

I have:

 

$post = preg_replace ("/\[user=(.*?)\]/is",uname2("$1"),$post);

 

and the function

 

function uname2($value){
$sql = "SELECT * FROM `users` WHERE `username`='$value'";
$res = mysql_query($sql) or die(mysql_error());
$row = mysql_fetch_assoc($res);

return "<a href=\"/profiles.php?user={$row['username']}\" style=\"text-decoration:none;\"><img src=\"/images/users/ui_{$row['level']}.png\" alt=\"\" border=\"0\"> {$row['username']}</a>\n";
}

 

My result: �

 

Basically I suppose the actually value inside the uname2 function isn't necessarily being passed.

[rajivgonsalves]

what is the contents of your $post variable

[marcus]

Should that matter?

 

$post = "[user=matt]";

 

 

[rajivgonsalves]

was just checking because I am trying the same thing out here and it seems to be working

[rajivgonsalves]

this should work

 

$post = preg_replace ("/\[user=(.*?)\]/eis","uname2('$1')",$post);

[marcus]

Worked like a charm, tyvm.