[SOLVED] preg_replace http:// in url.

[ted_chou12]

I tried to learn a bit, simple ones I understand, but hard ones I cant do, how do you replace the http:// in front of the url using preg replace?

$link = preg_replace("/^(http:\/\/)?(.*?)/i", "$1", $link);

This is what I got, it doesnt work at all.

I don't think is right anyways.

Thanks for your corrections.

Ted.

[ted_chou12]

sorry, I finally got it working... however, I am having a problem:

$links444 = preg_replace("`(http://)?(www.)?(.*?)`is", "$3", $link2);

for this code, when I tried wwww.domain.com, it strips the www. and becomes wdomain.com, I know I am bored , and picky, but is it possible to modify it a bit so that when there are wwww. or it detects something different, it doesn't remove the "www."? Thanks.

Ted

[rajivgonsalves]

your expression should be something like

 

$links444 = preg_replace("`^http://`is", "", $link2);