june_c21 Posted November 12, 2007 Share Posted November 12, 2007 hi, i not sure what wrong with my code , it return empty result. SELECT id, month, start_date, end_date, user.name, report.staff_no,details,amount,gl_code,user.bank,user.acc_no,status FROM user,report WHERE report.staff_no = user.staff_no Link to comment https://forums.phpfreaks.com/topic/76931-sql-error/ Share on other sites More sharing options...
teng84 Posted November 12, 2007 Share Posted November 12, 2007 report.staff_no = user.staff_no check if that condition is really satisfied ... or you might use left join Link to comment https://forums.phpfreaks.com/topic/76931-sql-error/#findComment-389524 Share on other sites More sharing options...
june_c21 Posted November 12, 2007 Author Share Posted November 12, 2007 i try left join but it doesn't work Link to comment https://forums.phpfreaks.com/topic/76931-sql-error/#findComment-389552 Share on other sites More sharing options...
teng84 Posted November 12, 2007 Share Posted November 12, 2007 can we see your php code within that statement? Link to comment https://forums.phpfreaks.com/topic/76931-sql-error/#findComment-389562 Share on other sites More sharing options...
june_c21 Posted November 12, 2007 Author Share Posted November 12, 2007 $query = "SELECT id, month, start_date, end_date, user.name, report.staff_no,details,amount,gl_code,user.bank,user.acc_no,status FROM user,report WHERE report.staff_no = user.staff_no"; $result = mysql_query($query, $dblink); while($myrow = mysql_fetch_row($result)) { echo "<tr><td><span class=style2>" . $myrow[0] . "</span</td>"; echo "<td><span class=style2>" . $myrow[1] . "</span</td>"; echo "<td><span class=style2>" . $myrow[2] . "</span</td>"; echo "<td><span class=style2>" . $myrow[3] . "</td></span>"; echo "<td><span class=style2>" . $myrow[4] . "</span></td>"; echo "<td><span class=style2>" . $myrow[5] . "</span></td>"; echo "<td><span class=style2>" . $myrow[6] . "</span></td>"; echo "<td><span class=style2>" . $myrow[7] . "</span></td>"; echo "<td><span class=style2>" . $myrow[8] . "</span></td>"; echo "<td><span class=style2>" . $myrow[9] . "</span></td>"; echo "<td><span class=style2>" . $myrow[10] . "</span></td>"; echo "<td><span class=style10>" . $myrow[11] . "</span></td>"; Link to comment https://forums.phpfreaks.com/topic/76931-sql-error/#findComment-389581 Share on other sites More sharing options...
teng84 Posted November 12, 2007 Share Posted November 12, 2007 <? $query = "SELECT id, month, start_date, end_date, user.name, report.staff_no,details,amount,gl_code,user.bank,user.acc_no,status FROM user,report WHERE report.staff_no = user.staff_no"; $result = mysql_query($query, $dblink) or die (mysql_error()); print_r(mysql_fetch_assoc($result )); ?> paste here the output... Link to comment https://forums.phpfreaks.com/topic/76931-sql-error/#findComment-389589 Share on other sites More sharing options...
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