[SOLVED] Undefined variable

[emediastudios]

I get this error

Notice: Undefined variable: count in C:\Program Files\Apache Group\Apache2\htdocs\Prepare2win\admin\upload_news.php on line 42

In my code below

 

<?php require_once('../Connections/p2w.php');
error_reporting(E_ALL);

//This is the directory where images will be saved 
$target = "../news/"; 

//This gets all the other information from the form 
$headline=$_POST['headline']; 
$contents=$_POST['contents']; 
$photo1=($_FILES['photo1']['name']); 
$photo2=($_FILES['photo2']['name']); 
$photo3=($_FILES['photo3']['name']);
$title1=$_POST['title1']; 
$title2=$_POST['title2'];
$title3=$_POST['title3'];  
$link=$_POST['link']; 
//Writes the photo to the server 
for ($x=1;$x<=3;$x++){
    $photo ='photo'.$x;
$target = "../news/" . basename( $_FILES[$photo]['name']);
if (($_FILES[$photo]["type"] == "image/gif")
|| ($_FILES[$photo]["type"] == "image/png")
|| ($_FILES[$photo]["type"] == "image/jpeg")
|| ($_FILES[$photo]["type"] == "image/pjpeg")
&& ($_FILES[$photo]["size"] < 1000000)){
	if(move_uploaded_file($_FILES[$photo]['tmp_name'], $target)){

		//Tells you if its all ok 

		echo "Success."; 
$photo="";

		} 
}
else { 

	//Gives and error if its not 
	++$count;
} 
}

if ($count > 0){                       ///////////////////////line 42//////////////////
echo $count .'failed to upload ';

}
else
{
//Writes the information to the database 

$host="localhost"; // Host name 
    $username="root"; // Mysql username 
    $password="5050888202"; // Mysql password 	 
$db_name="preparetowin"; // Database name 
    $tbl_name="news"; // Table name 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
    mysql_select_db("$db_name")or die("cannot select DB");
mysql_query("INSERT INTO `news` VALUES (NULL,'$headline','$contents','$photo1','$photo2','$photo3','$title1','$title2','$title3','$link')") ; 
print "<meta http-equiv=\"refresh\" content=\"0;URL=news_added_successfully.php\">";

}
?>

[cooldude832]

and what is line 42??

[bwochinski]

Initialize the variable before your for-loop.

$count = 0;            //      <<==========  Add this
//Writes the photo to the server 
for ($x=1;$x<=3;$x++){

 

 

(Edit: clarified addition)

[cooldude832]

what do you mean itialize $x=1 means $x = 1 its intialized

[emediastudios]

sorry but still getting errors, how would i add that to my code? thanks 4 the help guys.

[bwochinski]

I tried to clarify my previous post after cooldude posted...

 

You just need to add:

$count = 0;

 

At the top where you set up the rest of your variables before you start the for loop.

You're getting an error because if all the uploads in your script are successfull, $count is never incremented, so when you test for "  if ($count > 0)  ", it doesn't like the comparison of "  if ( NULL > 0 )  ".

[teng84]

I tried to clarify my previous post after cooldude posted...

 

You just need to add:

$count = 0;

 

At the top where you set up the rest of your variables before you start the for loop.

You're getting an error because if all the uploads in your script are successfull, $count is never incremented, so when you test for "  if ($count > 0)  ", it doesn't like the comparison of "  if ( NULL > 0 )  ".

 

this wont cause an error

if(NULL >0)  this is valid

even if you have null values it will still compare the two  but try also to initialize your variable maybe its a version issue of php

 

 

[emediastudios]

Thanks, that did the trick. :)

 

[teng84]

null == 0  //true

null === 0 // false

 

[bwochinski]

Yeah teng's right, so never mind my earlier attempt at an explanation.  Can't really say why what I recommended worked.