regular expressions help (date format)

[robcrozier]

HI all, i wonder if someone can help me with this.  Im not very good with regular expressions but i would like to use the ereg() function to check for a date in this format: yyyy/mm/dd.

 

any help appreciated!

 

Cheers all!

[dbo]

This is the wrong forum. But the regex is:

 

/^[0-9]{4}\/[0-9]{2}\/[0-9]{2}$/

 

To verify ranges and what not you'll need more than this though. That just validates the format. yyyy/mm/dd

 

 

[robcrozier]

sorry about the wrong forum but that doesn't seem to work?

[dbo]

Define doesn't work.

[BenInBlack]

I would say that dbo's regex is proper, but since you said you wanted it to work with ereg modified his code to wrap the items in () parens

 

to use with preg_replace

$output = preg_replace(/^([0-9]{4})\/([0-9]{1,2})\/([0-9]{1,2})$/,*,1977/1/1);

 

to use with ereg,

if (ereg ("([0-9]{4})\/([0-9]{1,2})\/([0-9]{1,2})", $date, $regs)) {

    echo "$regs[3].$regs[2].$regs[1]";

} else {

    echo "Invalid date format: $date";

}