mariocesar Posted November 26, 2007 Share Posted November 26, 2007 Please help, this script works fine in my machine I use Dreamwaver to build pages and when I test the page work perfectly fine, but when I upload it to the hosting server don't work, here is the scrip. <script language="javascript" type="text/javascript"> function showDetails(x) { document.getElementById('det').style.display=''; document.getElementById('img5').src="php_uploads/uploads/"+x; } function offDetails() { document.getElementById('det').style.display='none'; } </script> and this is the part where the image shows it self on mouse over: <table cellspacing="3" cellpadding="2" align="center" class="sample"> <tr> <td rowspan="4" height="80" width="180"><div align="center"><img src="php_uploads/uploads/161107040021.jpg" width="55" height="80" border="0" onMouseOver="javascript: showDetails('161107040021.jpg');" onMouseOut="javascript: offDetails();"></div></td> <td width="94">CR-80 <div align="left" style="position:absolute; display:none; padding-left:11px; padding-top:10px; padding-right:22px; background-color:#DFE6E3;" id="det"> <img src="" id="img5" name="ing5" style="border:0px solid #666666;"></div> </td> </tr></table> thanks. Quote Link to comment Share on other sites More sharing options...
phpQuestioner Posted November 27, 2007 Share Posted November 27, 2007 I do not know why you would be having problems with getting your script to work on your web host; unless you have an javascript error or conflict in another part of your page, that is affecting this script. because I run your script and it worked fine. you could try it like this, but it is basically the same as your original script: <script language="javascript"> function showDetails(x) { document.getElementById('det').style.display=''; document.getElementById('img5').src="php_uploads/uploads/"+x+""; } function offDetails() { document.getElementById('det').style.display='none'; } </script> <table cellspacing="3" cellpadding="2" align="center" class="sample"> <tr> <td rowspan="4" height="80" width="180"><div align="center"><img src="php_uploads/uploads/161107040021.jpg" width="55" height="80" border="0" onMouseOver="javascript: showDetails('161107040021.jpg');" onMouseOut="javascript: offDetails();"></div></td> <td width="94">CR-80 <div align="left" style="position:absolute; display:none; padding-left:11px; padding-top:10px; padding-right:22px; background-color:#DFE6E3;" id="det"> <img src="" id="img5" name="ing5" style="border:0px solid #666666;"></div> </td> </tr></table> Quote Link to comment Share on other sites More sharing options...
mariocesar Posted November 27, 2007 Author Share Posted November 27, 2007 Thanks, Questioner may be folder permissions? Quote Link to comment Share on other sites More sharing options...
phpQuestioner Posted November 27, 2007 Share Posted November 27, 2007 this is a basic/common JavaScript method; I do not know of any host that prevents this basic form of JavaScript. I guess it is possible though, but probably not likely. if you have any other code that goes with this script; you might want to check it for errors. Quote Link to comment Share on other sites More sharing options...
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