mike1313 Posted November 29, 2007 Share Posted November 29, 2007 I'm using the live data tutorial and I can't seem to get it to work. Any help? Ajax code: function createRequestObject() { var req; if(window.XMLHttpRequest){ // Firefox, Safari, Opera... req = new XMLHttpRequest(); } else if(window.ActiveXObject) { // Internet Explorer 5+ req = new ActiveXObject("Microsoft.XMLHTTP"); } else { // There is an error creating the object, // just as an old browser is being used. alert('There was a problem creating the XMLHttpRequest object'); } return req; } var http = createRequestObject(); function sendRequest2(act) { // Open PHP script for requests http.open('get', 'chatusers.php?act='+act); http.onreadystatechange = handleResponse2; http.send(null); } function handleResponse2() { if(http.readyState == 4 && http.status == 200){ // Text returned FROM PHP script var response2 = http.response2Text; if(response2) { // UPDATE ajaxTest content document.getElementById("users").innerHTML = response2; setTimeout('userc();' ,'2000'); } } } function userc() { sendRequest2('userc'); } and chat users.php <?php mysql_connect("dbhost","dbuser","pass"); mysql_selectdb("dbname"); $time = time()-100; if ($_GET['act'] == "userc") { $who = mysql_query("SELECT * FROM players WHERE lastcactive >= $time"); while ($who2 = mysql_fetch_array($who)) { echo "$who2[username]<br>"; } } ?> Note I've hidden my database also in the Ajax there's a 2 behind everything because I already have ajax running on the page updating a div that has the same names so 2's were added. Quote Link to comment Share on other sites More sharing options...
mike1313 Posted November 29, 2007 Author Share Posted November 29, 2007 I solved it. Quote Link to comment Share on other sites More sharing options...
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