Can you define a function's name with a variable?

[stompeers]

Hi folks!

 

This is my first post in PHP Freaks, I hope it's up to snuff.

 

Does anyone know if you can define a function name using a variable? For example:

 

$var = 'my_function_name';

function $var() {
}

 

I know you can't do that verbatim, as I've tried, but I was wondering if there is some workaround that would be valid?

 

Thanks!

Chris

[teng84]

$teng ='funcY';
function funcY(){
echo 'this is teng';
}
$teng();

 

you can have something like that 

[stompeers]

Thanks, I know that one is possible, but you still have to define the function knowing the function's name. I would like to define a function dynamically,without first knowing it's name. Is there any way to do that?

 

Thanks!

Chris

[pocobueno1388]

Why not just test it? Also, why would you want to do that?

[marcus]

Don't limit his options, he wants what he wants

[teng84]

dynamic creating of functions ? hmm i dont see any instance that you can use that

perhaps dynamic calling might be useful but dynamic creating of function?? 

[pocobueno1388]

Don't limit his options, he wants what he wants

 

I'm not limiting his options, I'm actually trying to do the opposite. I'm trying to figure out why in the world they would want to do that as I can't think of a single reason, and then maybe I can direct them to a better method.

[teng84]

Don't limit his options, he wants what he wants

 

I'm not limiting his options, I'm actually trying to do the opposite. I'm trying to figure out why in the world they would want to do that as I can't think of a single reason, and then maybe I can direct them to a better method.

 

yah meeeen im with you why would you waste your time in worthless things like this  ..

[btherl]

You can create functions without a name with create_function().

 

But for what you want you will need eval():

 

$newfunc = 'function foo() { print "foo\n"; }';
eval($newfunc);
foo();

[PHP_PhREEEk]

You can create functions without a name with create_function().

 

But for what you want you will need eval():

 

$newfunc = 'function foo() { print "foo\n"; }';
eval($newfunc);
foo();

 

That still creates the function with a known name ahead of time... I think he wants (if this even works... lol)

 

$someVar = 'someName';
$newfunc = 'function' . $someVar . '() { print "foo\n"; }';
eval($newfunc);
$someVar();

 

Now I have to go test that... haha

 

PhREEEk

[PHP_PhREEEk]

PHP didn't find the humor in that code at all... heheh

 

PhREEEk

[PHP_PhREEEk]

Missed a space... the code below prints foo

 

$someVar = 'someName';
$newfunc = 'function ' . $someVar . '() { print "foo\n"; }';
eval($newfunc);
$someVar();

 

PhREEEk

[btherl]

I assumed the OP would know that he could alter the string before calling eval()