[SOLVED] Javascript as a Form action

[Esqulax]

Hiya

 

Im trying to open a pop up window when a button is clicked..the code i have works at the bottom as an <a href...>, but wont do is as a form action at the top...any idea what im doing wrong?

 

<table border="0" width="730" align="center" bgcolor="">
<tr>
	<td colspan="4" align="center">
		<img src="image/guest/guestmain.gif">
         </td>
         </tr>

<tr align="center">
<form method="post" action="javascript: window.open('add.php', 'Add Guest', 'width =400, height = 400');">
	<td><button value="Add Guest" type="submit"><img src="image/guest/addguest.png" width=40 height=40></button></td>
     </form>
    
<!-- Other table elements, removed for forum-->

	<tr align="center">
            <td><a href="javascript: window.open('add.php', 'Add Guest', 'width =400, height = 400');"><img src="image/guest/addimg.gif"></a></td>


	</tr>
        
  	</table>

</body>
</html>

[BenInBlack]

ok, you use the onSubmit event for doing something when the form is submited, but I have no idea why on earth you want to do it on form action, I mean why a form, the form is not going to post the values to you popup window.

 

Is it so you dont have to create a button.

here is the code

<form method="post" onSubmit="window.open('add.php', 'Add Guest', 'width =400, height = 400'); return false;" action="">
	<td><button value="Add Guest" type="submit"><img src="image/guest/addguest.png" width=40 height=40></button></td>
</form>

[Esqulax]

i thought that the action was "When this form is submitted, do what it says in action"

evidently i was wrong, ah well.. live and learn, eh?

 

Thanks for your help!

[phpQuestioner]

your not going to be able to send your form variables to your pop-up window like this.