[SOLVED] Creating php code to put odd numbers in a table.

[talksr]

What sort of code can I make which will print odd numbers from 2 to 99 in a table on a webpage?

???

[pocobueno1388]

This will display all odd numbers between 2 and 99

 

<?php

for ($i=3; $i<100; $i+=2){
   echo $i.'<br>';
}

?>

 

I'm not sure how you want the table, so if you need help with that, explain it a little.

[cooldude832]

from 2 to 99 lol 2 is even prime and not odd

[talksr]

from 2 to 99 lol 2 is even prime and not odd

 

I have just realised that!  Sorry about the mistake.

 

Basically, I would like php to create the numbers and insert them into a table in a web page.

 

[pocobueno1388]

Basically, I would like php to create the numbers and insert them into a table in a web page.

 

Well, I gave you the code to generate the numbers...now all you have to do is generate the HTML you want. If you don't know how to do that, then give a description of how you want the table to look.

[talksr]

I know how to create a table, but not how to get the numbers into the table. I have no preference as to how the table looks, just want to try some things out really. Any help would be great. 

[pocobueno1388]

How about this?

 

<?php

echo '<table border=1>';

for ($i=3; $i<100; $i+=2){
   echo '<tr>';
   echo '<td>'.$i.'</td>';
   echo '</tr>';
}

echo '</table>';

?>

[talksr]

Thanks, looks good. If I wanted to add columns what could I insert into the php code, so say I wanted to use 3 or 5 columns to make it easier to fit on the page?

[pocobueno1388]

<?php

echo '<table border=1>';

$cols = 1;
for ($i=3; $i<100; $i+=2){

   echo '<td>'.$i.'</td>';

   if ($cols == 5){
      echo '<tr>';
      $cols = 0;
   }
   
   $cols++;
}

echo '</table>';

?>

[talksr]

Thanks for all of your help, thats super. Is there any way you can explain to me what is happening on these lines:

 

for ($i=3; $i<100; $i+=2){

 

and also

 

if ($cols == 5){
      echo '<tr>';
      $cols = 0;
   }

[revraz]

Start $i at 3, count up to 100, increment $i +2 because you want odd only.

 

Set cols to 1 and print $i in a row, count up to 5 and when you hit 5 start a new row.

[pocobueno1388]

This line

for ($i=3; $i<100; $i+=2){

 

Is telling $i to start at 3, increase by 2 each time the loop runs, and to run the loop 99 times (since you want all odd numbers up to 99.

 

   if ($cols == 5){
      echo '<tr>';
      $cols = 0;
   }

 

I set up a counter named $cols, this counts how many times the loop has run...so if it has run 5 times, then $cols equals 5.  So that code checks if the loop has run 5 times, and if it has, to create a new row (since you want 5 numbers per line). Then it starts the counter over for the next row.

 

Hopefully those make sense

[talksr]

Thanks pocobueno1388,and everyone else for your help 

[pocobueno1388]

No problem

 

Don't forget to press "topic solved".

[talksr]

No probs thanks again