nezbo Posted December 6, 2007 Share Posted December 6, 2007 Hi all I have this code and i cant get it to submit the same way as a submit button echo "<table cellspacing=1 class=\"modual\">"; echo "<form action=" . $_SERVER['PHP_SELF'] . " method=\"post\" name=\"userLogin\">"; echo "<tr class=\"tHedder\"><td><span class=small><strong>" . H_SIGN_IN . "</strong></span>"; echo "<tr class=\"modual\"><td><span class=small>" . F_USER_NAME . "</span><br><input type=text name=userName size=10 />"; echo "<br><span class=small>" . F_PASSWORD . "</span><br><input type=password name=password size=10 />"; echo "<br><div align=\"center\">"; ?> <input type="image" name="submitLogin" src="images/signin.gif" width="75" height="28" /> <?php echo "</div><div align=\"center\"><a href=\"forgotpassword.php\"><span class=small>" . L_FORGOT_PASSWORD . "</a></span></div>"; echo "<div align=\"center\"><a href=\"requestRegister.php\"><strong><span class=small>" . L_REQUEST_USER . "</a></span></strong></div></td></tr>"; echo "</form>"; echo "</table>"; has any one any idea how i can get it to work like a proper button? Neil Quote Link to comment Share on other sites More sharing options...
nezbo Posted December 6, 2007 Author Share Posted December 6, 2007 i have changed the 'post' to a 'get' on the form and it then shows in the address bar submitLogin.x=40&submitLogin.y=12 i am sure this is why me if (!$_post[submitLogin]) dose not work. Is there any way to stop the x.y being added? Neil Quote Link to comment Share on other sites More sharing options...
PFMaBiSmAd Posted December 6, 2007 Share Posted December 6, 2007 This will help - http://www.php.net/manual/en/faq.html.php#faq.html.form-image Quote Link to comment Share on other sites More sharing options...
nezbo Posted December 6, 2007 Author Share Posted December 6, 2007 that solved it cheers Quote Link to comment Share on other sites More sharing options...
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