acctman Posted December 7, 2007 Share Posted December 7, 2007 hi can someone assist me with the proper coding and placement for converting images to .jpg. Also if a check can be done to see if the image is already .jpg then don't convert but if the image is .png .bmp .jpeg .bmp .gif thanks in advance <?php $styles = '<link type="text/css" rel="stylesheet" href="css/imig.css" media="screen, projection" />'; include 'header.php'; if(isset($_POST['imageFileName'])) { // DEFINE VARIABLES $imageWidth = $_POST['imageWidth']; $imageFileName = $_POST['imageFileName']; $resizeWidth = $_POST['resizeWidth']; $sourceFile = "working/cropped/". $imageFileName; $destinationFile = "working/finished/" . $imageFileName; if(file_exists($destinationFile)) { chmod($destinationFile, 0777); unlink($destinationFile); } // delete if existing // CHECK TO SEE IF WE NEED TO CROP if($imageWidth != $resizeWidth) { $convertString = "convert $sourceFile -resize $resizeWidth $destinationFile"; exec($convertString); chmod($destinationFile, 0777); chmod($sourceFile, 0777); unlink($sourceFile); } else { // RESIZE WAS SKIPPED $cmd = "mv " . $sourceFile . " " . $destinationFile; exec($cmd); } ?> <div class="info"> <h1>All Done</h1> <p>Your image has been cropped and resized as you'd like. The image below can be used as you see fit.</p> </div> <div id="completedImage"> <?php echo "<img src=\"" . $destinationFile . "\" id=\"theImage\" alt=\"Final Image\" />"; $workingDir = exec('pwd'); $finalFile = $workingDir . "/" . $destinationFile; // echo "Final File Location: " . $finalFile; ?> </div> <!-- completedImage --> <?php } else { ?> <div class="info"> <h1>Error</h1> <p>There was an error.</p> </div> <?php } include 'footer.php' ?> Quote Link to comment https://forums.phpfreaks.com/topic/80686-convert-images-to-jpg/ Share on other sites More sharing options...
Wuhtzu Posted December 7, 2007 Share Posted December 7, 2007 How do you wanna do it? With PHP (gdlib functions) or Linux/Unix (using exec)? Quote Link to comment https://forums.phpfreaks.com/topic/80686-convert-images-to-jpg/#findComment-409246 Share on other sites More sharing options...
acctman Posted December 7, 2007 Author Share Posted December 7, 2007 How do you wanna do it? With PHP (gdlib functions) or Linux/Unix (using exec)? with imagemagick (www.imagemagick.org/script/convert.php) thats what i've been using to edit the resizing. linux method would be fine to which ever converts without making the file huge. Quote Link to comment https://forums.phpfreaks.com/topic/80686-convert-images-to-jpg/#findComment-409253 Share on other sites More sharing options...
helraizer Posted December 7, 2007 Share Posted December 7, 2007 Using GD you could do some like the following. (haven't tested it). <?php $extension = explode(".", $filename); $extension = $extension[count($extension)-1]; $extension = strtolower($extension); if($extension == "jpg" || $extension == "jpeg" || $extension == "pjpeg") { $image = imagecreatefromjpeg($picture); } elseif($extension == "png") { $image = imagecreatefrompng($picture); } elseif($extension == "gif") { $image = imagecreatefromgif($picture); } ?> //only put this tag in for syntax highlighting.. Use your code for trimming and resizing, perhaps. Then to save the file <?php //only put this tag in for syntax highlighting.. header ("Content-type : image/jpg"); ImageJpeg($image); ImageJpeg($image, "image.jpg"); ImageDestroy($image); <? Although I wouldn't recommend converting to jpg, though.. When converted from png, even though it's a lot smaller, the quality is pretty shocking.. so gif would be a better one. Hope that helps a bit Sam Quote Link to comment https://forums.phpfreaks.com/topic/80686-convert-images-to-jpg/#findComment-409295 Share on other sites More sharing options...
acctman Posted December 8, 2007 Author Share Posted December 8, 2007 i keep getting an error on this part ImageJpeg($image); ImageJpeg($image, "image.jpg"); ImageDestroy($image); Warning: imagejpeg(): supplied argument is not a valid Image resource in /home/rmb/public_html/testcrop/slide/last_step.php on line 35 Warning: imagejpeg(): supplied argument is not a valid Image resource in /home/rmb/public_html/testcrop/slide/last_step.php on line 36 Warning: imagedestroy(): supplied argument is not a valid Image resource in /home/rmb/public_html/testcrop/slide/last_step.php on line 37 Quote Link to comment https://forums.phpfreaks.com/topic/80686-convert-images-to-jpg/#findComment-409504 Share on other sites More sharing options...
helraizer Posted December 8, 2007 Share Posted December 8, 2007 i keep getting an error on this part ImageJpeg($image); ImageJpeg($image, "image.jpg"); ImageDestroy($image); Warning: imagejpeg(): supplied argument is not a valid Image resource in /home/rmb/public_html/testcrop/slide/last_step.php on line 35 Warning: imagejpeg(): supplied argument is not a valid Image resource in /home/rmb/public_html/testcrop/slide/last_step.php on line 36 Warning: imagedestroy(): supplied argument is not a valid Image resource in /home/rmb/public_html/testcrop/slide/last_step.php on line 37 I think you, in your part of the code, need to refrence $image more, or change $image in what I gave you to $destinationFile (or source file, depending on which is the first). Also I think you need the image production code in a seperate file to the HTML, then reference to it after the HTML in another document with <img src='last_step.php'> Hope that helps Sam Quote Link to comment https://forums.phpfreaks.com/topic/80686-convert-images-to-jpg/#findComment-409619 Share on other sites More sharing options...
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