[SOLVED] ways to use the shuffle

[czukoman20]

<?php
$numbers = range(1, 10);
srand((float)microtime() * 1000000);
shuffle($numbers);
foreach ($numbers as $number) {
    echo "$number ";
}
?>

 

That is the code that will shuffle numbers one through ten.

and output like this

 

4 9 8 10 7 1 6 2 5 3

 

Is there a way to use those numbers, and use them as variables for a code?

if there is.. how would you do it?

[pocobueno1388]

The numbers are all stored in the $numbers array.

 

echo $numbers[0];

Will print out the first number in the array. $number[1] will print out the second, and so on.

 

Is that what you want? I guess it depends on what your wanting to do.

 

 

[play_]

as variable name or values?

 

if it's name, then no.

[czukoman20]

what poco said should work, but dont go away, because i need to see if this works. Thanks

 

 

[czukoman20]

Is there a way to add the number inside the variable.

like $numbers[1] + 2 so it would = $numbers[3]

 

 

 

 

[pocobueno1388]

Is there a way to add the number inside the variable.

like $numbers[1] + 2 so it would = $numbers[3]

 

If you tell us what your trying to accomplish, I'm sure we can show you the best way to do it =]

 

But yes, you can do something like this

 

<?php

$i = 1;
$i +=3;

echo $numbers[$i]; //will print out as $numbers[4]

?>

[czukoman20]

Ok well i tried to do this earlier but nobody replied so.

I have code already

mysql_select_db('db215169417')
or die('Error, cannot select mysql database');
$userid_1 = 1;
$query = mysql_query("SELECT * FROM users WHERE userid_2='$userid_1'");
$values = mysql_fetch_array($query);
$nrRows = mysql_num_rows($query);
if($nrRows == 1){

This code gets the userid, and pulls information from the user and displays it.

For my site, they want it to be random, and so that the user doesn't see doubles until he has gone through every user.

 

So i thought ok. if i could generate a list of random numbers like we did up there, and use those to input into that userid_1 variable then i could display random. Im stuck at how to keep it all at 5 per page, and to keep it going after each time the variables change

 

Thats my goal

[czukoman20]

ideas?

[cooldude832]

[quote author=play_ link=topic=171232.msg757780#msg757780 date=1197171113]
as variable name or values?

if it's name, then no.
[/quote]

absolutely you can use them as name you can have dynamic variable naming

<?php
$numbers = range(1, 10);
srand((float)microtime() * 1000000);
shuffle($numbers);
foreach ($numbers as $number) {
    $.number = "Its a variable ".$number;
}
$i = 1;
while($i <11){
if(ISSET($.$i)){
echo $.$i."<br />";
}
$i++;
}
?>

should show 10 variables

[pocobueno1388]

If you want to display random, there is no need to do all that extra work with PHP, you can do it right in your query

 

SELECT * FROM users ORDER BY rand()

 

That will make the results from the database come back random. If you want to sort it by pages, look into pagination.

[czukoman20]

well i have some users in my database at different levels.

like guest premium and admin

 

premium users are the only ones that i'd use for this. and those are the ones with userid's greater than 0

so how would that work?

[pocobueno1388]

You would just change your query up a bit, like this

 

SELECT * FROM users WHERE userid > 0 ORDER BY rand()

[czukoman20]

ok i will try that tomorrow

 

[play_]

If you want to display random, there is no need to do all that extra work with PHP, you can do it right in your query

 

SELECT * FROM users ORDER BY rand()

 

That will make the results from the database come back random. If you want to sort it by pages, look into pagination.

 

That gave me a syntax error on line 6

$.number = "Its a variable ".$number;

[pocobueno1388]

Why do you have a period in front of the dollar sign?

$.number

 

[czukoman20]

ok so i have the code

mysql_select_db('db215169417')
or die('Error, cannot select mysql database');
$userid_1 = 1;
$query = mysql_query("SELECT * FROM users WHERE userid_2='$userid_1'");
$values = mysql_fetch_array($query);
$nrRows = mysql_num_rows($query);
if($nrRows == 1){

 

 

"SELECT * FROM users WHERE userid_2='$userid_1'" is the part. how would i impliment this. to get the userid_2 variable randomly instead of it = userid_1

[czukoman20]

mysql_select_db('db215169417')
or die('Error, cannot select mysql database');
$query = mysql_query("SELECT * FROM users WHERE userid_2 > 0 ORDER BY rand()");
$values = mysql_fetch_array($query);
$nrRows = mysql_num_rows($query);

 

I used that.... and it doesn't work.... is my code messed up in the

$query = mysql_query("SELECT * FROM users WHERE userid_2 > 0 ORDER BY rand()");

[czukoman20]

Nobody has any IDeA? 

seriously now.

[czukoman20]

Ok i figured it out.