blueman378 Posted December 11, 2007 Share Posted December 11, 2007 hi guys, well basically this is the code: <?php global $database; $q = "SELECT * FROM " . Games . " ORDER BY `gplays` ASC "; $result = $database->query($q) or die("Error: " . mysql_error()); /* Error occurred, return given name by default */ $num_rows = mysql_numrows($result); if( $num_rows == 0 ){ return 'Game Not Found!'; } while( $row = mysql_fetch_assoc($result) ) { echo $row[gName]"<tr> <td class='topgamerow'> <a href='showgame.php?game=".$row[gName]."'> ".$row[gName]."</a> </td><td class='topgamerow' align='right'> ".$row[gplays]." </td></tr>"; } ?> and this is the error Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ',' or ';' in C:\wamp\www\maingame.php on line 15 Link to comment https://forums.phpfreaks.com/topic/81142-solved-quick-echo-problem/ Share on other sites More sharing options...
~n[EO]n~ Posted December 11, 2007 Share Posted December 11, 2007 You missed single quote in $row[gName] should be $row['gName']... there are others too Link to comment https://forums.phpfreaks.com/topic/81142-solved-quick-echo-problem/#findComment-411738 Share on other sites More sharing options...
btherl Posted December 11, 2007 Share Posted December 11, 2007 This line echo $row[gName]"<tr> should be echo $row['gName'] . "<tr> Edit: Oops, yes you should have quotes around the gName too Link to comment https://forums.phpfreaks.com/topic/81142-solved-quick-echo-problem/#findComment-411739 Share on other sites More sharing options...
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