[SOLVED] Ouput

[gple]

Here is my code

<td><img src=\"../prod_images/" . $image . "\" height=90><br>".$image."</td>

 

$image=WEB 100% Cashmere Sweater 001resizedcashmere.jpg

 

Here is my output

http://mensfashiondirect.com/prod_images/WEB%20100%%20Cashmere%20Sweater%20001resizedcashmere.jpg

 

and the image is not showing up properly because of the '%' character in. any way around this.

[phpretard]

Can you use uderscores instead of spaces?

 

WEB_100%_Cashmere_Sweater_001resizedcashmere.jpg

 

[gple]

I can but I would like to have the spaces.

[~n[EO]n~]

I think rawurlencode will help

[gple]

This does not work. It adds pluses where the spaces are. Any other way I have coded it, I get % where spaces are. I dont need those.

[haku]

I got a 400 error so I couldn't see your output. But you have to add "echo" to the start of that image statement.

[rajivgonsalves]

rawurlencode should work

 

 

try

 

$image = rawurlencode($image);
echo "<td><img src=\"../prod_images/" . $image . "\" height=90>
".$image."</td>";

 

[rajivgonsalves]

or better still if u getting image as a paramter

 

$image = rawurlencode(urldecode($image));