Moron Posted December 18, 2007 Share Posted December 18, 2007 This line: echo "<img src=\"photos/$department/$filename\" width=120 height=160 border=5 bordercolor=blue>"; ....produces no image and the properties say: http://server/mainfolder/photos/Computer%20Services%20%20%20%20%20%20%20%20%20% Am I correct in assuming that the multiple "%20" entries at the end represent the remainder of the field? If so, how do I make it cut off after the last actual character? (I want the legitimate %20 spaces intact) Link to comment https://forums.phpfreaks.com/topic/82233-solved-truncate-after-last-character-in-field/ Share on other sites More sharing options...
chigley Posted December 18, 2007 Share Posted December 18, 2007 trim() maybe? Link to comment https://forums.phpfreaks.com/topic/82233-solved-truncate-after-last-character-in-field/#findComment-417914 Share on other sites More sharing options...
Moron Posted December 19, 2007 Author Share Posted December 19, 2007 trim() maybe? rtrim() did the trick. Thanks! Link to comment https://forums.phpfreaks.com/topic/82233-solved-truncate-after-last-character-in-field/#findComment-418208 Share on other sites More sharing options...
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