Moron Posted December 18, 2007 Share Posted December 18, 2007 This line: echo "<img src=\"photos/$department/$filename\" width=120 height=160 border=5 bordercolor=blue>"; ....produces no image and the properties say: http://server/mainfolder/photos/Computer%20Services%20%20%20%20%20%20%20%20%20% Am I correct in assuming that the multiple "%20" entries at the end represent the remainder of the field? If so, how do I make it cut off after the last actual character? (I want the legitimate %20 spaces intact) Quote Link to comment Share on other sites More sharing options...
chigley Posted December 18, 2007 Share Posted December 18, 2007 trim() maybe? Quote Link to comment Share on other sites More sharing options...
Moron Posted December 19, 2007 Author Share Posted December 19, 2007 trim() maybe? rtrim() did the trick. Thanks! Quote Link to comment Share on other sites More sharing options...
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