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[SOLVED] Truncate after last character in field?


Moron

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This line:

 

echo "<img src=\"photos/$department/$filename\" width=120 height=160 border=5 bordercolor=blue>";

 

....produces no image and the properties say:

 

http://server/mainfolder/photos/Computer%20Services%20%20%20%20%20%20%20%20%20%

 

Am I correct in assuming that the multiple "%20" entries at the end represent the remainder of the field?

 

If so, how do I make it cut off after the last actual character? (I want the legitimate %20 spaces intact)

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