kevinfwb Posted December 20, 2007 Share Posted December 20, 2007 I have a text box that is used to display a royalty rate. It the MySQL database it stores 5% as 0.05 (as it should be). However, they prefer to see it as %5.00 in the forms that they access. The line of code for the textBox is: echo " <td><input type=\"text\" name=\"adRate\" value=\"{$row['adRate']}\" /></td>\n"; I can't seem to get it to display the ad rate * 100 in the text box without using a second line of code to multiply the rate by 100 1st and then saving it to a variable and displaying the 2nd variable in the text box. Is arithmetic even possible in the "value" field? Thanks for your help -Kevin Link to comment https://forums.phpfreaks.com/topic/82545-solved-input-box-help/ Share on other sites More sharing options...
p2grace Posted December 20, 2007 Share Posted December 20, 2007 Try this: echo " <td><input type=\"text\" name=\"adRate\" value=\"".$row['adRate'] * 100."\" /></td>\n"; Link to comment https://forums.phpfreaks.com/topic/82545-solved-input-box-help/#findComment-419623 Share on other sites More sharing options...
kevinfwb Posted December 20, 2007 Author Share Posted December 20, 2007 Error still: Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ',' or ';' Thanks Link to comment https://forums.phpfreaks.com/topic/82545-solved-input-box-help/#findComment-419624 Share on other sites More sharing options...
p2grace Posted December 20, 2007 Share Posted December 20, 2007 Sorry, this will fix it: echo " <td><input type=\"text\" name=\"adRate\" value=\"".($row['adRate'] * 100)."\" /></td>\n"; Link to comment https://forums.phpfreaks.com/topic/82545-solved-input-box-help/#findComment-419628 Share on other sites More sharing options...
kevinfwb Posted December 20, 2007 Author Share Posted December 20, 2007 Indeed it did. Thanks a lot for you help -Kevin Link to comment https://forums.phpfreaks.com/topic/82545-solved-input-box-help/#findComment-419632 Share on other sites More sharing options...
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