mariocesar Posted December 20, 2007 Share Posted December 20, 2007 Hello, I have this script that pull info from a table pluss a link to an image allready in a folder, when you go over the image. it display the original image size, works fine the problem is that now I have more than 35 products and when the user roolls over the image the image displays ok but all the way to the top, so the user can not see the image, here is the script: <div align="center"><img src="<?php echo $row['productimage']; ?>" width="60" height="60" border="0" onMouseOver="javascript: showDetails('<?php echo $row['productimage']; ?>');" onMouseOut="javascript: offDetails();"> </div> <div align="left" style=" float:left; position:absolute; display:none; z-index:10; padding-left:11px; padding-top:10px; padding-right:11px; background-color:#DFE6E3;" id="det"> <img src="" id="img5" name="ing5" style="border:0px solid #666666; z-index:10;"></div> here is the js: <script language="javascript" type="text/javascript"> function showDetails(x) { document.getElementById('det').style.display=''; document.getElementById('img5').src=x; } function offDetails() { document.getElementById('det').style.display='none'; } </script> How can I see the image rigth on the screen, thanks Link to comment https://forums.phpfreaks.com/topic/82558-pop-out-shows-at-the-top/ Share on other sites More sharing options...
MadTechie Posted December 20, 2007 Share Posted December 20, 2007 wrong section.. please use the Javascript section Link to comment https://forums.phpfreaks.com/topic/82558-pop-out-shows-at-the-top/#findComment-419716 Share on other sites More sharing options...
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