simple string shell_exec puzzle

[LiquidGib]

In php, why does the following only print $msg?  The second variable $msgg is not printed.

 

                $msg = 'This is a hidden message 1234567890';

$msgg = 'This is a hidden message only meant for the person who is reading it 1234567890';

echo shell_exec("echo $msg");

echo shell_exec("echo $msgg");

[PHP_PhREEEk]

In php, why does the following only print $msg?  The second variable $msgg is not printed.

 

                $msg = 'This is a hidden message 1234567890';

$msgg = 'This is a hidden message only meant for the person who is reading it 1234567890';

echo shell_exec("echo $msg");

echo shell_exec("echo $msgg");

 

Remove the smiley face from $msgg and re-run the commands. does it print now?

 

PhREEEk

[LiquidGib]

yes, why it no likey smiley face?

[chigley]

Because Mr. Smiley Face contains a ) which screws it up