emancipator Posted December 25, 2007 Share Posted December 25, 2007 I am trying to write a very simple image displaying program, I am using HostMonster. The problem being: when i remove the function (ie. move everything outside of the function), everything works fine but when I put everything into the function (ie. code below) and execute it in the body, nothing gets displayed except the link (url). Any idea? Here is the code: <?php header('Content-type: image/jpeg'); function image(){ $filename = 'TEST.JPG'; $image = imagecreatefromjpeg($filename); imagejpeg($image,null,100); } ?> <html> <body> <?php image(); ?> </body> </html> Quote Link to comment Share on other sites More sharing options...
emancipator Posted December 25, 2007 Author Share Posted December 25, 2007 bump Quote Link to comment Share on other sites More sharing options...
Gamic Posted December 25, 2007 Share Posted December 25, 2007 The script that is outputing an image should be a seperate script from one outputing html. You should do something like this with your html code so that your browser can make a request to the server for the image. <image src="path/to/imageScript.php"> Quote Link to comment Share on other sites More sharing options...
emancipator Posted December 27, 2007 Author Share Posted December 27, 2007 Thanks for the reply. I still don't quite understand the difference between image operation and say echoing something, and how do I pass function parameters if I can't really "call" the function in html. I guess my question remains how do I execute a function that does image manipulation (like create a thumb size picture page based on a list of pictures). Sorry for being so noob-ish, and thanks in advance for replying. Quote Link to comment Share on other sites More sharing options...
Barand Posted December 27, 2007 Share Posted December 27, 2007 You need a "thumb.php" script that creates a thumnail size image of the file passed to it <?php $picToResize = $_GET['pic'] $src = imagecreatefromjpeg($picToResize); // resize code here imagejpeg ($thumbImage); imagedestroy($src); imagedestroy($thumb): ?> In your main page you then output a series of img tags to output the thumbnail images, passing the file to process in the query string. EG <?php $images = array ('a.jpg', 'b.jpg', 'c.jpg'); foreach ($images as $picture) { echo "<img src='thumb.php?pic=$picture'>"; } Quote Link to comment Share on other sites More sharing options...
emancipator Posted December 27, 2007 Author Share Posted December 27, 2007 Thanks for the reply. When I tried this echo "<img src='thumb.php?pic=$picture'>"; It doesn't seem to pass $picture to thumb.php but instead display thumb.php?pic=$picture, which is obviously a broken link. Any ideas? Quote Link to comment Share on other sites More sharing options...
emancipator Posted December 28, 2007 Author Share Posted December 28, 2007 bump ... again Quote Link to comment Share on other sites More sharing options...
spiffy577 Posted December 28, 2007 Share Posted December 28, 2007 If it is displaying literally "<img src='thumb.php?pic=$picture'>", just take the $picture out of the string quote, like this: echo "<img src='thumb.php?pic=".$picture." '>"; Although I could be COMPLETELY missing the point but I had the same problem sometimes with keeping the variable within the echo'd string. And btw, I am not exactly an expert on php but isn't image a keyword? So using image as a function name wouldn't work. Change the name to createImage or something... Although again, I could be completely missing the point. hehe... Quote Link to comment Share on other sites More sharing options...
emancipator Posted December 28, 2007 Author Share Posted December 28, 2007 Thanks, that is a part of the solution but not all. The main problem remains as the PUT and GET action isn't initiated in the img tag but merely passed along as a part of the url. Does this have anything to do with on_load? I am lost... Quote Link to comment Share on other sites More sharing options...
emancipator Posted December 29, 2007 Author Share Posted December 29, 2007 Bump. Quote Link to comment Share on other sites More sharing options...
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