Pagination

[hbalagh]

I think I almost have this i have it so it only shows 12 images on the first page of each category but can't figure out how the link should be and get it to work..  i've done this before on another site but it didn't have categories to deal with, the code is a little messy right now.. but hoping someone can help me on this

 

Thanks

 

<?php

include ("includes/db.conf.php");
include ("includes/connect.inc.php");include ("header.php");
if (isset($_GET['cat'])){
$query = "SELECT * from products where category='$_GET[cat]' ";
$mysqlresult = mysql_query($query);

$queryc=mysql_query("select * from categories where id='$_GET[cat]' ");
$rowqueryc=mysql_fetch_array($queryc);
echo "<div id='featureindex'>";
echo "<h3>$rowqueryc[name]</h3>";
}
   $qry = mysql_query ("
       SELECT * FROM `products` where category='$_GET[cat]'");
      if ($row=mysql_fetch_array($qry))
      {
        do 
        {
          $sName= $row["name"];
          $sphoto= $row["photo"];
          $sdescription= $row["description"];
        } while ($row = mysql_fetch_array($qry));
      }
    $limit          = 12;                
    $query_count    = "SELECT count(*) FROM `products` where category='$_GET[cat]'";     
   $result_count   = mysql_query($sName);     
$totalrows      = mysql_num_rows($qry); 
    	if(empty($page)){ 
        $page = 1; 
    } 
     $limitvalue = $page * $limit - ($limit); 
    $query  = "SELECT * FROM `products` where category='$_GET[cat]' LIMIT $limitvalue, $limit";         
    $result = mysql_query($query) or die("Error: " . mysql_error()); 
    if(mysql_num_rows($result) == 0){ 
        echo("Nothing to Display!"); 
    } 
   while($row = mysql_fetch_array($result)){ 
   
echo "<div id='feature'><a href='product.php?product=$row[id]'><div id='productborder'><img src='images/thumbs/$row[photo]' border=0></div></a>";
echo($row["name"]); 
echo "</div>\n";
    } 
echo "<br />\n";
  
    $numofpages = $totalrows / $limit; 
    for($i = 1; $i <= $numofpages; $i++){ 
        if($i == $page){ 
            echo($i." "); 
        }else{ 
            echo("<a href=\"productlist.php?cat=$rowqueryc[id]page=$i\">$i</a> "); 
        } 
    } 
    if(($totalrows % $limit) != 0){ 
        if($i == $page){ 
            echo($i." "); 
        }else{ 
            echo("<a href=\"productlist.php?cat=$rowqueryc[id]page=$i\">$i</a> "); 
        } 
   	echo "</div>\n";
    } 
    mysql_free_result($result); 
include_once 'footer.php';
?>

[Northern Flame]

well i found a mistake on your script

 

on all the sql commands you have something like this:

 

"SELECT * FROM categories WHERE id='$_GET[cat]'"

 

you are forgetting the single quotes around the word cat

 

try making it a variable and do something like

 

$cat = $_GET['cat'];

$change_queries_to = mysql_query("SELECT * FROM categories WHERE id='$cat'");

[tibberous]

Can also be:

 

$change_queries_to = mysql_query("SELECT * FROM categories WHERE id='{$_GET['cat']}'");

[redarrow]

or

 

<?php
$queryc=mysql_query("select * from `categories` where `id`='".$_GET['cat']."' ");
$rowqueryc=mysql_fetch_array($queryc);
?>

[hbalagh]

thanks, but i still get confused by terminology the technical terms and after changing the below still can't get the links to work for it...

 

 

or

 

<?php
$queryc=mysql_query("select * from `categories` where `id`='".$_GET['cat']."' ");
$rowqueryc=mysql_fetch_array($queryc);
?>

 

 

[Northern Flame]

did you follow the tutorial from phpfreaks?

(if so, there have been people that have been having troubles with

it and I have a fix for it)

[hbalagh]

did you follow the tutorial from phpfreaks?

(if so, there have been people that have been having troubles with

it and I have a fix for it)

 

yes for the most part

[hbalagh]

can anyone offer anymore help on this

[Northern Flame]

http://www.phpfreaks.com/forums/index.php/topic,172220.msg763400.html#msg763400

[hbalagh]

I am still very lost and can't get it to work