Problem with if statement that should return true

[oskare100]

Hello,

This is the code snippet:

 

$breadcrumbtrail = $breadcrumb->trail(' » ');
$breadcrumbexploded = explode(";", $breadcrumbtrail);
echo $breadcrumbexploded[0];
if ($breadcrumbexploded[0] == "&RAQUO") {
echo "true";
} else {
echo "false";
}

 

That code returns the text "&RAQUOfalse" but it should return "&RAQUOtrue" since $breadcrumbexploded[0] == "&RAQUO". I can't figure out why it can't understand that $breadcrumbexploded[0] actuallt is &RAQUO.

 

Best Regards

Oskar R

 

 

   

[PHP_PhREEEk]

What does this say?

 

<?php
$breadcrumbtrail = $breadcrumb->trail(' » ');
$breadcrumbexploded = explode(";", $breadcrumbtrail);
var_dump($breadcrumbexploded[0]);
if ($breadcrumbexploded[0] == "&RAQUO") {
echo "true";
} else {
echo "false";
}

 

PhREEEk

[cooldude832]

you use two things you don't define

the function trail

and the variable $breadcrumb

explain those and we can see why

 

also try

print_r($breadcrumbexploded); to see the array's  content

[czukoman20]

if ($breadcrumbexploded[0] == "&RAQUO") {

 

why is $raque in the beginning lowercase ... then in the if capitalized... try making then the same

[cooldude832]

its not $ its & and &RAQUO is the proper xhtml way to display a < symbol so maybe you could do

<?php
$str = strreplace("&RAQUO;","<",$string);
$parts = explode("<",$str);
if($parts[0] != ""){
//Do something
}
?>