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Variable question


TimUSA

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How would I wrap this code up so that it was one variable?

 

echo'
<SELECT id="name" name="name[ ]" style="WIDTH: 160px" value ="';
if (isset($_POST['name[ ]'])) echo $_POST['name[ ]'];
echo '" />';

if(mysql_num_rows($result)) {
// we have at least one user, so show all users as options in select form
while($row=mysql_fetch_assoc($result)){
    echo '<option value="',$row['memberName'],'">',$row['memberName'],'</option>';
}
}
++$x;
}

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are you going to change this dynamically? 

 

if not, why not just make a function

call it stuff()

 

function stuff(){
echo'
<SELECT id="name" name="name[ ]" style="WIDTH: 160px" value ="';
if (isset($_POST['name[ ]'])) echo $_POST['name[ ]'];
echo '" />';

if(mysql_num_rows($result)) {
// we have at least one user, so show all users as options in select form
while($row=mysql_fetch_assoc($result)){
    echo '<option value="',$row['memberName'],'">',$row['memberName'],'</option>';
}
}
++$x;
}}

 

Then where you want that particular piece to go. call the function

 

<?php
stuff();
?>

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this poses the same problem i have been having.

 

when ever i try to loop this code it returns blanks in the dropdown box.

leave it with out the loop and it works fine and returns the appropriate database values

 

here is the full code i am working with now:

$query = "SELECT `memberName` FROM `smf_members` WHERE `ID_GROUP` IN (1, 9, 10, 11, 13) ORDER BY `memberName`;";
$result = mysql_query($query);
$times = 13;
$x = 0;

function stuff() {
echo'
<SELECT id="name" name="name[ ]" style="WIDTH: 160px" value ="';
if (isset($_POST['name[ ]'])) echo $_POST['name[ ]'];
echo '" />';

if(mysql_num_rows($result)) {
// we have at least one user, so show all users as options in select form
while($row=mysql_fetch_assoc($result)){
    echo '<option value="',$row['memberName'],'">',$row['memberName'],'</option>';
}
}
++$x;
}

$x=0;
while($x<$times){
stuff();
++$x;
}

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