[SOLVED] Show a file if exists?

[djfox]

If the file dolls/images/doll_user$user[1].png ($user[1] grabbed from a database table) exists, I need the file to show, but if it doesn`t exist, it needs to show a message. I have the following code:

<?php
if (dolls/images/doll_user$user[1].png) {
echo "<img src'dolls/images/doll_user$user[1].png'>";
}
else {
echo "You haven`t created a doll yet!";
}
?>

 

But this message appears:

Parse error: syntax error, unexpected T_VARIABLE in /home/secrett1/public_html/trancer_header2.php on line 157

 

Line 157 is:

if (dolls/images/doll_user$user[1].png) {

 

I guess for an actual file, the code needs to be different?

[revraz]

Need to use file_exists

 

http://us3.php.net/function.file-exists

[djfox]

<?php
$dollfile = 'dolls/images/doll_user$user[1].png' ;
if (file_exists($dollfile)) {
echo "<img src'$dollfile'>";
}
else {
echo "You haven`t created a doll yet!";
}
?>

 

It`s telling me he file doesn`t exist but I know it does. If I were to put in plainly:

<img src="dolls/images/doll_user$user[1].png">

the file loads.

 

Did I do something wrong in my code?

[papaface]

Try:

<?php
$dollfile = 'dolls/images/doll_user'.$user[1].'.png' ;
if (file_exists($dollfile)) {
echo "<img src='".$dollfile."'>";
}
else {
echo "You haven`t created a doll yet!";
}
?>

[djfox]

Changed

echo "<img src'".$dollfile."'>";

 

to

echo "<img src='".$dollfile."'>";

 

And it worked! Thanks for the help!