[SOLVED] Load and output image without uploading (bandwidth spending)?

[Full-Demon]

Hi,

 

I have a script where I have to load a certain image and than output the image, but I don't want it that the server has to upload the image and than let the user download: I want the user to just download from the original fileserver (where the image is stored).

 

So I have:

File server (images stored here) -> Script server (with the actual script) -> User

 

Users use the image tag to load the image: <img src="site.com/myscript.php">

I thought about this for my script:

<?php
$array = array('img1.png', 'img2.png');
header("Location: othersite.com/".$array[rand(0, 1)]);
?>

 

That works, except that it is not random! The output is always one image and if you reload it never switches to the other one!

 

How can I make this like I want?

 

Thank you a lot!

FD

 

 

[MadTechie]

this should work..

 

<?php
$array = array('img1.png', 'img2.png');
$rand = array_rand($array);
header("Location: othersite.com/".$array[$rand]);
?>

 

but then again yours looks fine as well...

 

[Full-Demon]

Thanks for the reply, but it still doesn;t work.

 

It looks like the client/browser doesn't reload the image...I even tried it with the no-cashing headers, but neither works.

 

How can I force the client to reload the image?

[MadTechie]

erm.. maybe

 

<?php
header("Cache-Control: no-cache, must-revalidate"); // HTTP/1.1
header("Expires: Mon, 26 Jul 1997 05:00:00 GMT"); // Date in the past

$array = array('img1.png', 'img2.png');
$rand = array_rand($array);
header("Location: othersite.com/".$array[$rand]."?Rand=".time());
?>

 

depends how your calling that page itself..

[Full-Demon]

Ah that worked!

 

Thanks a lot