forumnz Posted January 1, 2008 Share Posted January 1, 2008 Yes, this should be in this section... I have a triple drop down box AJAX feature. Someone chooses an option from the 1st, which loads the second etc. I have a heirarchy db type thing like: PID ID 0 1 0 2 1 3 1 4 1 5 1 6 2 7 The drop down box is meant to SELECT WHERE pid (parent id) = 0, to start off. Then (using above example) say user clicks value (ID) 2, number 7 loads (ID 7 with PID 2). The problem is that The second dropdown box (as far as I got), always loads the items with PID 0 (like the first box). This is the main code that matters. I have enclosed the 3rd section in /* */, so just ignore it. <? header ("Expires: Sat, 26 Jul 2008 05:00:00 GMT"); header ("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); header ("Cache-Control: no-cache, must-revalidate"); header ("Pragma: no-cache"); header("content-type: application/x-javascript; charset=tis-620"); $data=$_GET['data']; $val=$_GET['val']; $dbhost = "localhost"; $dbuser = "aaa"; $dbpass = "aaa"; $dbname = "aaa"; mysql_pconnect($dbhost,$dbuser,$dbpass) or die ("Unable to connect to MySQL server"); if ($data=='province') { echo "<select name='province' onChange=\"dochange('amper', this.value)\">\n"; $result=mysql_db_query($dbname,"SELECT * from ffcats where pid ='0' ORDER BY name"); while($row = mysql_fetch_array($result)) { $name1 = $row['name']; $id1 = $row['id']; $a = $id1; echo "<option value=\"$id1\" >$name1</option> \n" ; } } else if ($data=='amper') { echo "<select name='amper' onChange=\"dochange('tumbon', this.value)\">\n"; echo "<option value='0'>======== 2 ========</option>\n"; $val = substr($val,0,2); $result=mysql_db_query($dbname,"SELECT * FROM ffcats WHERE pid ='$a' ORDER BY name"); while($row = mysql_fetch_array($result)) { $name2 = $row['name']; $id2 = $row['id']; echo "<option value=\"$id2\" >$name2</option> \n" ; } } /*else if ($data=='tumbon') { echo "<select name='tumbon' >\n"; echo "<option value='0'>======== 3 ========</option>\n"; $val2=$val; $val = substr($val,0,4); $result=mysql_db_query($dbname,"SELECT loc_code, loc_abbr, loc_name, location_name FROM location WHERE loc_code != '000000' and loc_code != '$val2' AND loc_code LIKE '$val%' AND flag_disaster IS NULL ORDER BY loc_code, loc_abbr"); while(list($id, $name)=mysql_fetch_array($result)){ echo "<option value=\"$id\" >$name</option> \n" ; } }*/ echo "</select>\n"; ?> Please help if you can, Sam. Link to comment https://forums.phpfreaks.com/topic/83951-php-help-with-ajax/ Share on other sites More sharing options...
Barand Posted January 1, 2008 Share Posted January 1, 2008 there is an example in my sig using AJAX (sample application) for dependent selection lists Link to comment https://forums.phpfreaks.com/topic/83951-php-help-with-ajax/#findComment-427249 Share on other sites More sharing options...
larsbrimmer Posted January 30, 2009 Share Posted January 30, 2009 forumnz did you ever get this to work for you. I have the same script and am having problems with the second list. Link to comment https://forums.phpfreaks.com/topic/83951-php-help-with-ajax/#findComment-750457 Share on other sites More sharing options...
landavia Posted January 30, 2009 Share Posted January 30, 2009 forumnz did you ever get this to work for you. I have the same script and am having problems with the second list. interesting.. but the result for TS are confuse us i think the problem are the place you put your script in my ajax (same problem).. I put 3 div (this div was the place where list will be).. hmm.. it's kinda hard to explain <div name=text1>/*my 1st list goes here */<div> <div name=text2>/*my 2st list goes here, the 1st list are selecter */<div> <div name=text3>/*my 3rd list goes here, where 2nd list already selected */<div> sry.. not much to help you should try this example there 3 list = A, B, C A is Nation like Washington DC, California etc B is name of City C is name of street Link to comment https://forums.phpfreaks.com/topic/83951-php-help-with-ajax/#findComment-750465 Share on other sites More sharing options...
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