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Wrong var posted to DB


forumnz

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I have a user select their region from a drop down list. I want some regions to be isolated and some to include others (if that makes sense). Anyway, the user submits the form with the region value. The variable is named $region.

 

I wrote this extra but, but the script still inserts 0 into all three db columns.

 

if($region == 0)
{
$reg1 == 0;
$reg2 == 0;
$reg3 == 0;
}
elseif($region >=2 && $region <=13)
{
$reg1 == 0;
$reg2 == 2;
$reg3 == $region;
}
elseif($region >=14 && $region <=21)
{
$reg1 == 0;
$reg2 == 14;
$reg3 == $region;
}

 

Thanks for your help!

Sam.

 

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https://forums.phpfreaks.com/topic/84380-wrong-var-posted-to-db/
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Ok here it is:

 

<?php
$buzzname=$_POST['buzzname'];
$sub=$_POST['sub'];
$descr=$_POST['descr'];
$keyw=$_POST['keyw'];
$addst=$_POST['addst'];
$addsu=$_POST['addsu'];
$addci=$_POST['addci'];
$region=$_POST['region'];
$addpc=$_POST['addpc'];
$ph=$_POST['ph'];
$ph2=$_POST['ph2'];
$freeph=$_POST['freeph'];
$fax=$_POST['fax'];
$email=$_POST['email'];


if($region == 0)
{
$reg1 == 0;
$reg2 == 0;
$reg3 == 0;
}
elseif($region >=2 && $region <=13)
{
$reg1 == 0;
$reg2 == 2;
$reg3 == $region;
}
elseif($region >=14 && $region <=21)
{
$reg1 == 0;
$reg2 == 14;
$reg3 == $region;
}

$uid = $_SESSION['id'];

include('dbcon.php');

$sql="INSERT INTO cmads (buzzname, sub, descr, keyw, addst, addsu, addci, region, region2, region3, addpc, userid, ph, ph2, freeph, fax, email) VALUES ('$buzzname','$sub','$descr','$keyw','$addst','$addsu','$addci','$reg1','$reg2','$reg3','$addpc','$uid','$ph','$ph2','$freeph','$fax','$email')";

if (!mysql_query($sql))
  {
  die('Error: ' . mysql_error());
  }
echo "1 record added" . $reg1 . $reg2 . $reg3 . "<br>" . $region;

?>

 

As you can see at the bottom I echoed the three regions, but it only displayed:

1 record added
13

Like this?

 

if($region == '0')
{
$reg1 == '0';
$reg2 == '0';
$reg3 == '0';
}
elseif($region >='2' && $region <='13')
{
$reg1 == '0';
$reg2 == '2';
$reg3 == $region;
}
elseif($region >='14' && $region <='21')
{
$reg1 == '0';
$reg2 == '14';
$reg3 == $region;
}

 

Still doesn't work.

 

Any ideas?

Sam.

Change the == to = within the body of the if's

>:( Bah, can't believe I missed that. Oh well, that happens when you're skimming code at work.

 

@forumnz: I generally use d ouble quotes for everything except for inside square ([ ]) brackets. I have no idea if one or the other is better/faster in terms of code execution or parsing.

Single quotes are faster. Using double quotes will basically trigger PHP to look for variables within the string which will cause some unnecessary checking. The following article provides some optimization tips when coding in PHP so read it if you want:

 

http://tiger-inc.com/php/optimize-your-code/

so ..

echo 'This is a string';

would be faster than?

echo "This is a string";

 

 

 

 

yep becouse ' single quotes dont phase throw php like  double quotes....

 

in other words php use the " double quotes to do somethink with..........

 

example

<?php
echo ' this is a litrall  $redarrow will not be echoed out';

$redarrow='hi there i am redarrow';

echo"this is a phased  $redarrow will echo";
?>

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