Confused/Baffled

[Dysan]

If the $string variable contains "101010" in the following code, the width of the barcode displayed is larger than if the $string variable contained "111111".

 

But, if "101010" is entered into the textbox displayed on at the following URL, and the "Generate Barcode" button is clicked, the barcode displayed is the same width than if "111111" was entered into the textbox.

 

URL: www.sid6581.net/cs/php-scripts/barcode/

 

The only difference is the barcode display is slightly different, to reflect the diffrent value entered.

 

What needs to be changed in the following code, in order for the bar code to display the same width, regardless of the barcode value. Like it does in the demo found at the above URL?

 

<?php
$rectangle_width = 2;
$rectangle_height = 100;

$image = imagecreatetruecolor(300, 188);
$white = imagecolorallocate($image, 255, 255, 255);
$black = imagecolorallocate($image, 0, 0, 0);

imagefill($image, 0, 0, $white);
imagerectangle($image, 0, 0, 298, 186, $black);

$find = array('0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '*');
$replace = array('1010001110111010', '1110100010101110', '1011100010101110', '1110111000101010', '1010001110101110', '1110100011101010', '1011100011101010', '1010001011101110', '1110100010111010', '1011100010111010', '1000101110111010');

$string = '*111111*';
$textstring = str_replace($find, $replace, $string);

$j = 11;
$sarray = str_split($textstring, 1);
for($i = 0; $i < count($sarray); $i++)
{
    if($sarray[$i] ==  '0')
    {
        imagefilledrectangle($image, $rectangle_width * $j, 150, ($rectangle_width * $j) + $rectangle_width, $rectangle_height, $white);
        $j++;
        
    }
    elseif($sarray[$i] ==  '1')
    {
        imagefilledrectangle($image, $rectangle_width * $j, 150, ($rectangle_width * $j) + $rectangle_width, $rectangle_height, $black);
        $j++;
    }
} 

imagettftext($image, 10, 0, 120, 170, $black, "Verdana", $string);

header("Content-type: image/jpeg");
imagejpeg($image);
imagedestroy($image);
?>