Dysan Posted January 12, 2008 Share Posted January 12, 2008 The following code encodes a string into a bar code. Everything works fine except, when 0's are entered into the string. - Why is this? Upon entering one or more 0's into the string variable (e.g. "101010"), the bar code generated for some reason enlarges in width, rather than staying the same. However, the code found at the following URL, works perfectly. How do I get my code to run like the code at the following URL, where the bar code width doesn't change upon entering "111111", "101010" or any other six digit value? URL: http://www.sid6581.net/cs/php-scripts/barcode/ - Click "Download the PHP script". Any Help Would Be Greatly Appreciated! - I am well and truly stuck! <?php $rectangle_width = 2; $rectangle_height = 100; $image = imagecreatetruecolor(300, 188); $white = imagecolorallocate($image, 255, 255, 255); $black = imagecolorallocate($image, 0, 0, 0); imagefill($image, 0, 0, $white); imagerectangle($image, 0, 0, 298, 186, $black); $find = array('0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '*'); $replace = array('1010001110111010', '1110100010101110', '1011100010101110', '1110111000101010', '1010001110101110', '1110100011101010', '1011100011101010', '1010001011101110', '1110100010111010', '1011100010111010', '1000101110111010'); $string = '*111111*'; $textstring = str_replace($find, $replace, $string); $j = 11; $sarray = str_split($textstring, 1); for($i = 0; $i < count($sarray); $i++) { if($sarray[$i] == '0') { imagefilledrectangle($image, $rectangle_width * $j, 150, ($rectangle_width * $j) + $rectangle_width, $rectangle_height, $white); $j++; } elseif($sarray[$i] == '1') { imagefilledrectangle($image, $rectangle_width * $j, 150, ($rectangle_width * $j) + $rectangle_width, $rectangle_height, $black); $j++; } } imagettftext($image, 10, 0, 120, 170, $black, "Verdana", $string); header("Content-type: image/jpeg"); imagejpeg($image); imagedestroy($image); ?> Quote Link to comment Share on other sites More sharing options...
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