[SOLVED] Simple Constant Problem?

[ctroyp]

I have a constant that I am passing into an if statement.  Unfortunately, it is not evaluating correctly. 

 

// Constant
define('_GROUP1', '$group == "Silver Member" || $group == "Gold Member"');

 

...

 

$group = "Silver Member";

if( _GROUP1 ){
echo "Success";
}

 

"Success" does not print.

 

Thanks for any help...I know this is trivial.

[twostars]

I have a constant that I am passing into an if statement.  Unfortunately, it is not evaluating correctly. 

 

// Constant
define('_GROUP1', '$group == "Silver Member" || $group == "Gold Member"');

 

...

 

$group = "Silver Member";

if( _GROUP1 ){
echo "Success";
}

 

"Success" does not print.

 

Thanks for any help...I know this is trivial.

Can you even use constants that way? I didn't think you could.

[cooldude832]

I have a constant that I am passing into an if statement.  Unfortunately, it is not evaluating correctly. 

// Constant
define('_GROUP1', '$group == "Silver Member" || $group == "Gold Member"');

 

You can't define a constant that way, secondly its very poor strucutre thirdly you are trying to call a constant by variable value.

why not just say

<?php
if($group == "Silver Member"){
//Do this
}
elseif($group == "Gold Member"){
//do that
}
?>

[twostars]

I have a constant that I am passing into an if statement.  Unfortunately, it is not evaluating correctly. 

// Constant
define('_GROUP1', '$group == "Silver Member" || $group == "Gold Member"');

 

You can't define a constant that way, secondly its very poor strucutre thirdly you are trying to call a constant by variable value.

why not just say

<?php
if($group == "Silver Member"){
//Do this
}
elseif($group == "Gold Member"){
//do that
}
?>

You can define the constant that way.

 

However, I agree - you really can't use it like that.

[Daukan]

you cant really use a constant that but you can do this

<?php
if(defined('_GROUP1') ){
?>

 

edited: _GROUP1 needed to be wrapped in quotes

[cooldude832]

you can't because you have no argument for the Or statement it shouldn't randomly pick  on its own

[twostars]

you can't because you have no argument for the Or statement it shouldn't randomly pick  on its own

Its not going to parse the statement, so whatever is in it will be completely irrelevant, but the constant itself would be quite valid, which is the point I'm trying to make.

 

But yeah, the if ( _GROUP1 ){ wouldn't work at all.

[Daukan]

You can do this

<?php
define('_GROUP1', $group == "Silver Member" ? "Silver Member" : "Gold Member");
?>

[twostars]

You can do this

<?php
define('_GROUP1', $group == "Silver Member" ? "Silver Member" : "Gold Member");
?>

In which case $group would need to be declared and defined prior to the define.

[Daukan]

You can do this

<?php
define('_GROUP1', $group == "Silver Member" ? "Silver Member" : "Gold Member");
?>

In which case $group would need to be declared and defined prior to the define.

 

Oh I assumed he was seeding $group via database or cookie. Either way that makes for some odd coding.

 

[ctroyp]

My constant is defined in a single file and will be accessed from multiple files. 

 

Here is what I am ultimately trying to do...  I need to be able to define a number of items to a variable with global access.  And in any given file, I want to see if the logged user's group is in the list (a large list) of items in that global variable.  So, do I need to use an array or is there a better way to achieve this?

[Daukan]

An array would do it probably.

<?php
$user['group'] = 'group2';
$GLOBALS['groups'] = array('group1', 'group2', 'group3', 'group4');

if(in_array($user['group'], $GLOBALS['groups']) ) {
    echo 'You are in a group';
}
?>

[ctroyp]

I decided to go the array route similar to Daukan's post.  Thanks to all for the help.