PHP Functional programming

[keenlearner]

I need to to a little functional programming, my question is in the code. Thanks.

 

<?php
function print1($arg1, $arg2)
{
  echo 'Print 1 function : ';
  var_dump($arg1);
  var_dump($arg2);
}

function print2($arg1,$arg2)
{
  echo 'Print 2 function : ';
  var_dump($arg1);
  var_dump($arg2);
}

function applyOne($arg1,$funcName)
{
  if(is_array($arg1)) $code = "return $funcName(/*How should I write here for array ? Thanks*/ ,\$arg2)";
  else  $code = "return $funcName(\"$arg1\", \$arg2);";

  return create_function('$arg2', $code);
}

//this is working
$printFunction = applyOne('string 1', 'print1');
$printFunction('arg2 string');

//'This is not working, how to make it work for array ? But note that the array may contain other type of objects, not just string. Thanks.
class obj {
   function __construct(){}
}
$obj = new obj();
$printFunction = applyOne(array($obj), 'print2');
$printFunction('arg2 string');

?>

 

Can I have the array that has been passed to stay alive until passed to the print function ?

[sKunKbad]

if you want to pass a value into a class, then the variable needs to be declared as public, and then on the outside you would use $obj->variableName = 'whatever';

 

is that what you are asking?

[keenlearner]

Thanks for the reply, but sorry that is not what I mean. In short, I want to get the function print2 executed. I need this line to be completed. But not sure how to implement that, thanks.

if(is_array($arg1)) $code = "return $funcName(/*How should I write here for array ? Thanks*/ ,\$arg2)";

 

It's so difficult in PHP in contrast to Javascript.

[sKunKbad]

If you want to return something from the $funcName, then you have to return the result from inside the function, and then apply it to a variable for further use. Maybe I don't fully understand, but looking at your line of code, that was what came to mind. When I get stuck, I go back to basics. Check this out:

 

<?php
function getPath(){
$path = getcwd();
return $path;
}

echo "Your Absoluthe Path is: ";
$whatever = getPath();
echo $whatever;
?>

 

 

[keenlearner]

I think my question is not very clear, but really appreciate of your help. I think maybe this is the solution.  The key is the var_export

Or any other advice for me ? Many thanks.

<?php

function print1($arg1, $arg2)
{
  echo 'Print 1 function : ';
  var_dump($arg1);
  var_dump($arg2);
  echo '<br>';
}

function print2($arg1,$arg2)
{
  echo 'Print 2 function : ';
  var_dump($arg1);
  var_dump($arg2);
  echo '<br>';
}

function applyOne($arg1,$funcName)
{
  if(is_array($arg1))
    {
      $str = var_export($arg1,true);
      $code = "return $funcName( $str ,\$arg2);";
    }
  else  $code = "return $funcName(\"$arg1\", \$arg2);";

  return create_function('$arg2', $code);
}

$printFunction = applyOne('string 1', 'print1');
$printFunction('arg2 string');


class obj {
  public $var1;
   function __construct(){}

   function __set_state($array)
   {
     $obj = new obj;
     $obj->var1 = $array['var1'];
     return $obj;
   }
}
$obj = new obj();
$obj->var1 = 'variable 1';
$printFunction = applyOne(array($obj), 'print2');
$printFunction('arg2 string');

?>