[SOLVED] ORDER BY problem

pkenny9999 · January 14, 2008

I am trying to make the results from a query output in a certain order, I realize that I have some other issues with my code, but I'm going problem at a time. How do I take the results and Order them by the field 'address' and also how do I get it to omit the street number and sort by the first letter of the street name? Here's the code so far, I have tried the following code $query = "SELECT * FROM Address ORDERED BY address;" but I recieve Query Failed.

/* Performing SQL query */

$query = "SELECT * FROM Address";

$first_one = 1;

if($lastname != "") {

if($first_one == 1) {

$query = "$query WHERE";

$first_one = 0;

$query = "$query lastname LIKE '%$lastname%'";

}

else {

$query = "$query AND lastname LIKE '%$lastname%'";

}

if($address != "") {

if($first_one == 1) {

$query = "$query WHERE";

$first_one = 0;

$query = "$query address LIKE '%$address%'";

}

else {

$query = "$query AND address LIKE '%$address%'";

}

if($city != "") {

if($first_one == 1) {

$query = "$query WHERE";

$first_one = 0;

$query = "$query city LIKE '%$city%'";

}

else {

$query = "$query AND city LIKE '%$city%'";

}

if($zipcode != "") {

if($first_one == 1) {

$query = "$query WHERE";

$first_one = 0;

$query = "$query zipcode LIKE '%$zipcode%'";

}

else {

$query = "$query AND zipcode LIKE '%$zipcode%'";

}

if($territory != "") {

if($first_one == 1) {

$query = "$query WHERE";

$first_one = 0;

$query = "$query territory = '$territory'";

}

else {

$query = "$query AND territory = '$territory'";

}

$result = mysql_query($query) or die("Query failed");

/* Printing results in HTML */

$numresult = mysql_num_rows($result);

print "<h4 align=center>";

print $numresult;

print " results match your search<h4>\n";

print "<table cellpadding=6 border=0 align=center>\n";

print "\t<tr align=left bgcolor=#CCCCCC>\n\t\t<td width=30>ID</td>\n\t\t<td width=125>Last Name</td>\n\t\t<td width=125>First Name</td>\n";

print "\t\t<td width=175>Address</td>\n\t\t<td width=125>City</td>\n";

print "\t\t<td width=75>Territory<td width=40>Delete</td></tr>\n";

while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {

</script>

<td><?php print "<a href='../address_edit.php?idx=";

print $line["address_id"];

print "'target=_new>";

print $line["address_id"];

print "</a>";?></td>

<td><?php print "<a href='../delete_address.php?idx=";

print $line["address_id"];

print "'target=_blank>";

print "<img src=../images/trash_icon.jpg border=0 alt='Delete Address' /img>";

print "</a></td>"; ?>

</tr>

<?php

}

print "</table>\n";

adam291086 · January 14, 2008

$query = "SELECT * FROM Address ORDERED BY address

should be

$query = "SELECT * FROM Address ORDER BY address"

pkenny9999 · January 14, 2008

Sorry, I mistyped the command I used, I used $query = "SELECT * FROM Address ORDER BY address"; and I get Query failed.

Ken2k7 · January 14, 2008

Sorry, I mistyped the command I used, I used $query = "SELECT * FROM Address ORDER BY address"; and I get Query failed.

Where did you use that? I don't see it in the code.

Also, please use

tags.

revraz · January 14, 2008

Post the mysql_error that you get. It will state where it fails.

Use ORDER BY Address instead of address if the field has a cap in it.

pkenny9999 · January 14, 2008

This is the code that does NOT work:

/* Performing SQL query */
	$query = "SELECT * FROM Address ORDER BY address";
	$first_one = 1;
	if($lastname != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query lastname LIKE '%$lastname%'";
		}
		else {
			$query = "$query AND lastname LIKE '%$lastname%'";
		}
	}
	if($address != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query address LIKE '%$address%'";
		}
		else {
			$query = "$query AND address LIKE '%$address%'";
		}
	}
	if($city != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query city LIKE '%$city%'";
		}
		else {
			$query = "$query AND city LIKE '%$city%'";
		}
	}
	if($zipcode != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query zipcode LIKE '%$zipcode%'";
		}
		else {
			$query = "$query AND zipcode LIKE '%$zipcode%'";
		}
	}
	if($territory != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query territory = '$territory'";
		}
		else {
			$query = "$query AND territory = '$territory'";
		}
	}

	$result = mysql_query($query) or die("Query failed");

	/* Printing results in HTML */
	$numresult = mysql_num_rows($result);

	print "<h4 align=center><font color=#3C94C4>";
	print $numresult;
	print " results match your search<h4></font>\n";
	print "<table cellpadding=6 border=0 align=center>\n";
	print "\t<tr align=left bgcolor=#CCCCCC>\n\t\t<td width=30><strong>ID</strong></td>\n\t\t<td width=125><strong>Last Name</strong></td>\n\t\t<td width=125><strong>First Name</strong></td>\n";
	print "\t\t<td width=175><strong>Address</strong></td>\n\t\t<td width=125><strong>City</strong></td>\n";
	print "\t\t<td width=75><strong>Territory</strong><td width=40><strong>Delete</strong></td></tr>\n";

	while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
	</script>
  <tr align="left">
  	<td><font size="1"><?php print "<a href='../address_edit.php?idx=";
				print $line["address_id"];
				print "'target=_new>";
				print $line["address_id"];
				print "</a>";?></font></td>
    <td><font size="1"><?php echo  $line["lastname"]; ?></font></td>
    <td><font size="1"><?php echo $line["firstname"]; ?></font></td>
    <td><font size="1"><?php echo $line["address"]; ?></font></td>
    <td><font size="1"><?php echo $line["city"]; ?></font></td>
    <td><font size="1"><?php echo $line["territory"]; ?></font></td>
<td><font size=1><?php print "<a href='../delete_address.php?idx=";
				print $line["address_id"];
				print "'target=_blank>";
				print "<img src=../images/trash_icon.jpg border=0 alt='Delete Address' /img>";
				print "</a></font></td>"; ?>
  </tr>
  <?php 
} 
print "</table>\n";

Ken2k7 · January 14, 2008

Put ORDER BY at the end of the $query string. So before you call mysql_query, put ORDER BY in there then.

pkenny9999 · January 14, 2008

I'm not exactily sure what the correct syntax would be to do that.

Would it go after

else {

$query = "$query AND territory = '$territory' ORDER BY address";

?

revraz · January 14, 2008

Just add it before the query

sasa · January 14, 2008

try

/* Performing SQL query */
	$query = "SELECT * FROM Address ";
	$first_one = 1;
	if($lastname != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query lastname LIKE '%$lastname%'";
		}
		else {
			$query = "$query AND lastname LIKE '%$lastname%'";
		}
	}
	if($address != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query address LIKE '%$address%'";
		}
		else {
			$query = "$query AND address LIKE '%$address%'";
		}
	}
	if($city != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query city LIKE '%$city%'";
		}
		else {
			$query = "$query AND city LIKE '%$city%'";
		}
	}
	if($zipcode != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query zipcode LIKE '%$zipcode%'";
		}
		else {
			$query = "$query AND zipcode LIKE '%$zipcode%'";
		}
	}
	if($territory != "") {
		if($first_one == 1) {
			$query = "$query WHERE";
			$first_one = 0;
			$query = "$query territory = '$territory'";
		}
		else {
			$query = "$query AND territory = '$territory'";
		}
	}
	$query .= 'ORDER BY address';
	$result = mysql_query($query) or die("Query failed");

	/* Printing results in HTML */
	$numresult = mysql_num_rows($result);

	print "<h4 align=center><font color=#3C94C4>";
	print $numresult;
	print " results match your search<h4></font>\n";
	print "<table cellpadding=6 border=0 align=center>\n";
	print "\t<tr align=left bgcolor=#CCCCCC>\n\t\t<td width=30><strong>ID</strong></td>\n\t\t<td width=125><strong>Last Name</strong></td>\n\t\t<td width=125><strong>First Name</strong></td>\n";
	print "\t\t<td width=175><strong>Address</strong></td>\n\t\t<td width=125><strong>City</strong></td>\n";
	print "\t\t<td width=75><strong>Territory</strong><td width=40><strong>Delete</strong></td></tr>\n";

	while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
	</script>
  <tr align="left">
  	<td><font size="1"><?php print "<a href='../address_edit.php?idx=";
				print $line["address_id"];
				print "'target=_new>";
				print $line["address_id"];
				print "</a>";?></font></td>
    <td><font size="1"><?php echo  $line["lastname"]; ?></font></td>
    <td><font size="1"><?php echo $line["firstname"]; ?></font></td>
    <td><font size="1"><?php echo $line["address"]; ?></font></td>
    <td><font size="1"><?php echo $line["city"]; ?></font></td>
    <td><font size="1"><?php echo $line["territory"]; ?></font></td>
<td><font size=1><?php print "<a href='../delete_address.php?idx=";
				print $line["address_id"];
				print "'target=_blank>";
				print "<img src=../images/trash_icon.jpg border=0 alt='Delete Address' /img>";
				print "</a></font></td>"; ?>
  </tr>
  <?php 
} 
print "</table>\n";

pkenny9999 · January 14, 2008

That did it! Thank you Sasa.

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[SOLVED] ORDER BY problem

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