[SOLVED] PHP in a 'search form'

[richard_PHP]

Hi,

 

Part of my assignment using PHP is to create a search function within a car website. What I've done is a drop down list that gets the records from a database and displays them.

 

However, because there are multiple car makes in the database they come up several times.

 

Code:

 

<?php

// Start the connection to the database

$conn = mysql_pconnect("**", "**", "**");

// Select the database to use

mysql_select_db("**",$conn);

// Select records from the database

$result = mysql_query ("SELECT * FROM ** LIMIT 0 , 50");

?>

<form name='myform' action='searchresult.php' method='post'>

<p><select name='chosen' tabindex='1'>

<option value="" selected="selected">Select..</option>

<?php while ($row=mysql_fetch_array($result)) //loops through results

                {

                echo "<option value=".$row['make'].">".$row['make']."</option>";

                }

            ?>

</select></p>

<p><input type='submit' value='Submit' tabindex='2' /></p>

</form>

<p></p>

 

I'm wanting the list to display 'Aston Martin, BMW, Ferrari" etc. But what it's really showing is "Aston Martin, BMW, BMW, Ferrari, Ferrari".

 

(BMW and Ferrari have multiple cars).

 

Please help, much appreciated.

[adam291086]

I think that is more of an issue with your database structure. You have repeating data in your table which should of been removed in the first steps of normalisation

[richard_PHP]

So there is no way at all to get rid of the extra makes? ???

[adam291086]

Whats your database structure. In your make feild do you have Astin Martin DB9 or just Astin Martin

[richard_PHP]

Just Aston Martin.

 

The fields I'm wanting to use for the search form is 'make' and 'model'.

 

The search form above uses 'make' to list in the drop-down and the search result displays the whole car using 'make' and 'model'.

[adam291086]

sorry there is away

 

i forgot about

 

Select DISTINCT Names FROM table;

will return astin martin once

[richard_PHP]

Changed code:

 

<?php

// Start the connection to the database

$conn = mysql_pconnect("**", "**", "**");

// Select the database to use

mysql_select_db("**",$conn);

// Select records from the database

$result = mysql_query ("SELECT DISTINCT * FROM ** LIMIT 0 , 50");

?>

<form name='myform' action='searchresult.php' method='post'>

<p><select name='chosen' tabindex='1'>

<option value="" selected="selected">Select..</option>

<?php while ($row=mysql_fetch_array($result)) //loops through results

                {

                echo "<option value=".$row['make'].">".$row['make']."</option>";

                }

            ?>

 

And it's still bringing up multiple results. I'll give you the list as it appears:

 

"Aston Martin

BMW

BMW

Ferrari

Ferrari

Mercedes-Benz

Mercedes-Benz

Mitsubishi

Nissan

Noble

Noble

Porsche

Porsche

Porsche

Subaru

Subaru

TVR

Vauxhall"

 

Grrr..  Lol..

[adam291086]

<?php
         // Start the connection to the database
         $conn = mysql_pconnect("**", "**", "**");
         // Select the database to use
         mysql_select_db("**",$conn);
         // Select records from the database
         $result = mysql_query ("SELECT DISTINCT * FROM ** LIMIT 0 , 50");
         ?>
         <form name='myform' action='searchresult.php' method='post'>
         <p><select name='chosen' tabindex='1'>
         <option value="" selected="selected">Select..</option>
         <?php while ($row=mysql_fetch_array($result)) //loops through results
                {
                echo "<option value=".$row['make'].">".$row['make']."</option>";
                }
            ?>

 

should be

 

<?php
         // Start the connection to the database
         $conn = mysql_pconnect("**", "**", "**");
         // Select the database to use
         mysql_select_db("**",$conn);
         // Select records from the database
         $result = mysql_query ("SELECT DISTINCT make FROM table_name LIMIT 0 , 50");
         ?>
         <form name='myform' action='searchresult.php' method='post'>
         <p><select name='chosen' tabindex='1'>
         <option value="" selected="selected">Select..</option>
         <?php while ($row=mysql_fetch_array($result)) //loops through results
                {
                echo "<option value=".$row['make'].">".$row['make']."</option>";
                }
            ?>

[richard_PHP]

Brilliant! That did the job! Thanks. 

[adam291086]

Hope you get an A in this project and the correct places of references marked down e.g phpfreak.com - adam291086

 

 

HAHAHAHA

[richard_PHP]

Lol.. Thanks. And I will with the reference.