[SOLVED] DIFFERENCE 18 years

[crashmaster]

Hi there,

 

need to check difference between

 

$now = time(); and for ex. $date = ("1990-01-19");      Difference in years...

 

If differnce 18 years its OK, if not -> BAD

 

I did it like this, but its not worK

 

$now = time();
$birthday = strtotime($_POST['year]."-".$_POST['month']."-".$_POST['day']) ;

if ( ($now - $birthdat) < (60*60*24*365*18) ) {
    return TRUE;
} else {
    return FALSE;
}

 

 

When I choose day: 17.01.1990 - its says that is OK, but its not true... This man, whos date 17.01.1990 will have 18 years only tomorrow.... Can comebody Help me ??

[revraz]

http://www.phpfreaks.com/forums/index.php/topic,177408.0.html