Problem uploading picture

Perfidus · January 17, 2008

I'm trying to upload, resize and create a thumbnail for a picture, at the same time, I introduce some info about it in a database.

The problem is that nothing happens when I execute the form, not even an error message.

Any hints?

<?
$msg = "";
switch(!strcasecmp($_SERVER['REQUEST_METHOD'], "POST")) {

   case true:

if(!isset($_FILES['image']) || $_FILES['image'] == "none" || $_FILES['image'] == "") {
	$msg = "<span class=\"Estyle3\">Select a picture from your PC</span>";
	break;
}
$conn = mysql_connect("","",""); 
mysql_select_db("",$conn);
$sql = "INSERT INTO pictures (desc, refoto) ";
$sql .= "VALUES ('$desc', '$refoto')";
$result = mysql_query($sql) or die(mysql_errno().'<p>'.$sql.'</p>'.mysql_error());

$tmp = getcwd()."/".$_FILES['image']['name'];

if(!@move_uploaded_file($_FILES['image']['tmp_name'], $tmp)) {

	$msg = "<span class=\"Style3\">There was a problem uploading your picture</span>";
	break;
}

$fp = fopen($tmp, "rb");
$str = fread($fp, filesize($tmp));

fclose($fp);
unlink($tmp);

$im1 = ImageCreateFromString($str);

$imgname = $refoto."thumb_1";
$maxwidth = 300;	
$maxheight = 150;	
$width1 = ImageSX($im1);
$height1 = ImageSY($im1);
$width2 = $maxwidth;
$height2 = floor(($width2 * $height1) / $width1);

if($maxheight > 0 && $height2 > $maxheight) {

	$height2 = $maxheight;
	$width2 = floor(($height2 * $width1) / $height1);
}

$im2 = ImageCreateTrueColor($width2, $height2);
ImageCopyResampled($im2, $im1, 0, 0, 0, 0, $width2, $height2, $width1, $height1);

ImageJpeg($im2, "fotos/thumb/".$imgname.".jpg");	
$msg = "Ok";
$im3 = ImageCreateFromString($str);

$imgname2 = $refoto."_1";	
$maxwidth2 = 800;		
$maxheight2 = 250;	

$width12 = ImageSX($im3);
$height12 = ImageSY($im3);
$width22 = $maxwidth2;
$height22 = floor(($width22 * $height12) / $width12);

if($maxheight2 > 0 && $height22 > $maxheight2) {

	$height22 = $maxheight2;
	$width22 = floor(($height22 * $width12) / $height12);
}

$im4 = ImageCreateTrueColor($width22, $height22);
ImageCopyResampled($im4, $im3, 0, 0, 0, 0, $width22, $height22, $width12, $height12);

ImageJpeg($im4, "fotos/full/".$imgname2.".jpg");			
break;
}

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Documento sin título</title>
<link rel=stylesheet href="thestyle.css" type="text/css">
</head>

<body>
<form id="form1" name="form1" method="post">
    <input type="file" name="image" size="20">
    <input type="hidden" name="value" value="a">
    <input type="hidden" name="refoto" value="b45546">
    
    <br />
    Picture description(20 caracteres) <br />
  
  <label>
  <input name="desc" type="text" id="desc" size="20" maxlength="20" />
  </label>
  <label>
  <input type="submit" name="Submit" value="SEND" />
  </label>
</form>
</body>
</html>

adam291086 · January 17, 2008

When you setup the form creditias you should have something like this. Yours has no action or enctype. Therefore how is the form supposed to know where to send the results?

<form action="uploader.php" method="post"
enctype="multipart/form-data">

Perfidus · January 17, 2008

Normally you need to set the "action" for the form, but when it referres to itself it will work without it, if I put the action content it wont work neither...

adam291086 · January 17, 2008

OK, didn't realsie that about the action. But you have to include the

enctype="multipart/form-data"

part. As it tell the form you are unloading a file.

also put

error_reporting(E_ALL); at the top of your code. This will throw out all errors.

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Problem uploading picture

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