horaliar Posted April 28, 2006 Share Posted April 28, 2006 I'm trying to display the table results in a new page and haven't been able to do so. Basically, what my script does, is run two count queries against a mysql table and display the results. If there are results, an additional button is displayed and from here the user would click the button in case the query details are needed. This is where I'm stuck.... I can redirect the page to another one, but the variables are not passed to the new page so I can run my query. I can't even find out a way to display the results in the same page! Please help! Any ideas will be appreciated, I haven't found any help anywhere else. Link to comment https://forums.phpfreaks.com/topic/8658-displaying-table-results/ Share on other sites More sharing options...
sanfly Posted April 28, 2006 Share Posted April 28, 2006 Can you post some code? Link to comment https://forums.phpfreaks.com/topic/8658-displaying-table-results/#findComment-31776 Share on other sites More sharing options...
horaliar Posted April 28, 2006 Author Share Posted April 28, 2006 Thank you sanfly. Actually, I posted all of the code in my next posting. It's called compact code. I appreciate any help you can give me, I've been going nuts trying to get this going on.It's actually named compact script. Link to comment https://forums.phpfreaks.com/topic/8658-displaying-table-results/#findComment-31785 Share on other sites More sharing options...
.josh Posted April 28, 2006 Share Posted April 28, 2006 have you looked into using sessions? or is that what you're doing and you are having issues. Link to comment https://forums.phpfreaks.com/topic/8658-displaying-table-results/#findComment-31786 Share on other sites More sharing options...
horaliar Posted April 28, 2006 Author Share Posted April 28, 2006 No, I'm just posting the form. Link to comment https://forums.phpfreaks.com/topic/8658-displaying-table-results/#findComment-31817 Share on other sites More sharing options...
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