kittiiekat Posted April 28, 2006 Share Posted April 28, 2006 I'm baffled. I'm trying to run an INSERT query via a PHP page and the query appears to be running twice. I went through the page and commented out various sections until I isolated the line that would appear to be causing the problem... but it doesn't make any sense to me. The line in question is this:<img src="<?php echo $row[image]; ?>">If $row[image] has a value, there is no problem. However, if it is NULL or the value is blank, the row is inserted into the database twice. Can anybody explain to me why this would happen? Thanks :) Quote Link to comment Share on other sites More sharing options...
milesperhour1086 Posted April 28, 2006 Share Posted April 28, 2006 post some code Quote Link to comment Share on other sites More sharing options...
kittiiekat Posted April 28, 2006 Author Share Posted April 28, 2006 It doesn't matter what the INSERT query I run is, every one I try behaves as expected if I run it directly from terminal in mysql or if $row[image] has a value. I've tried running a test using a very basic page and I get the same problem. The entire code for the page is as follows:<?php $conn = @mysql_connect('localhost', 'user', 'password'); if (!$conn) { echo '<p><b>error:</b> cannot connect to server</p>'; exit(); } if (!@mysql_select_db('database')) { exit('<p><b>error:</b> could not locate database</p>'); } mysql_query("INSERT INTO test VALUES ('2', 'my name')");?><html><body><img src=""></body></html>If I use <img src="">, I get the insert entered twice. If I use <img src="asdf">, it works fine. Quote Link to comment Share on other sites More sharing options...
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