supanoob Posted April 29, 2006 Share Posted April 29, 2006 well, i am trying to do a gym for my Browser based game. now i know what i want to do i just dont know where to start.now the basic idea is i want to add a random number between 0.1 and 0.7 to the number that is already in the database (which to start with is 10) then i want it to update it straight away. any advice on how to do this? Quote Link to comment Share on other sites More sharing options...
Orio Posted April 29, 2006 Share Posted April 29, 2006 Something like this?<?php$sql="SELECT num FROM `table` WHERE user='$user'";$result=mysql_query($sql);$the_num=mysql_result($result, 0);$rand=rand(0,7);$rand=$rand/10;$update=$the_num+$rand;$sql2="UPDATE `table` SET num='$update' WHERE user='$user'";if(mysql_query($sql2)){echo("updated");}?>Orio. Quote Link to comment Share on other sites More sharing options...
supanoob Posted April 29, 2006 Author Share Posted April 29, 2006 Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/content/A/r/c/ArchAngel390/html/game/power.php on line 24i get that error :Sthis is the code after i changed what i thought needed to be changed[code]<?phpsession_start();require_once('header.php');if (!$_SESSION['valid_user']) { echo 'you are not logged in'; die();} $user=$_SESSION['valid_user'];$query="select playerid, user, email, gold, fatigue, maxfat, power, speed, dex, intel, health, maxhealth, gender from players where user='$user'";$result=mysql_query($query);if (!$result){die (mysql_error());}$num_rows=mysql_num_rows($result);$sql="SELECT power FROM $tablename WHERE user='$user'";$result=mysql_query($sql);$power=mysql_result($result, 0);$rand=rand(0,7);$rand=$rand/10;$update=$the_num+$rand;$sql2="UPDATE `table` SET num='$update' WHERE user='$user'";if(mysql_query($sql2)){echo "you gained $rand power";die();}{echo "Power is now $power";die();}?>[/code] Quote Link to comment Share on other sites More sharing options...
.josh Posted April 30, 2006 Share Posted April 30, 2006 so which one is line 24? i think it might be here:$sql2="UPDATE `table` SET num='$update' WHERE user='$user'";shouldn't 'table' actually be your table name instead of 'table' ?i see earlier on in the code you have a table named players and then after that you refer to your table name as $tablename Quote Link to comment Share on other sites More sharing options...
Brandon Jaeger Posted April 30, 2006 Share Posted April 30, 2006 [code]$result=mysql_query($query);if (!$result){die (mysql_error());}[/code]A slight optimization:[code]$result=mysql_query($query) or die(mysql_error());[/code] Quote Link to comment Share on other sites More sharing options...
supanoob Posted April 30, 2006 Author Share Posted April 30, 2006 thanks i will let you know how i get on :D Quote Link to comment Share on other sites More sharing options...
supanoob Posted April 30, 2006 Author Share Posted April 30, 2006 well, good news it works kinda :Pi click the train button. and it adds to the power. but evey time it does so it resets the power to 1 instead of adding it to the 10 that is alread in there.for example i click it once, and it added .2 to my power. so i went and checked the database to make sure i added and the power was then 1.2. so i went and clicked again and gained .7 and check the database and it was 1.7 instead of the 10.9 i wanted it too be :( Quote Link to comment Share on other sites More sharing options...
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