[SOLVED] Warning: key(): Passed variable is not array

[phpdolan]

Any suggestions on how the following should be coded?

The desire is to return the number of the first key in the array.

Here's what I've got, which results in the Subject Warning.

 

The code:

reset($hi1_array[$j_date]);

$first = key($hi1_array[$j_date]);

 

The multidimensional array (one key): It typically has 40 keys.

[1]=>

  array(6) {

    ["off_duty"]=>

    string(2) "DO"

    ["date"]=>

    string(1) "1"

    ["jdate"]=>

    string(1) "1"

    ["day"]=>

    string(3) "Tue"

    ["min_307"]=>

    float(0)

    [307]=>

    string(4) "8:21"

 

Thanks for any replies.

 

[cooldude832]

have you tried writting your arrays like

<?php
$data = array();
$data['1']['Name'] = "joe";
$data['1']['Age'] = "27";
$data['2']['Name'] = "george";
$data['2']['Age'] = "32";
?>

 

A lot easier to read as I can not follow what you threw out without tabs

[teng84]

try

 

$first = key($hi1_array);

 

because it says its not an array maybe your $hi1_array[$j_date] is no longer an array(multidimensional)..

[phpdolan]

Thanks cooldude832 and teng82,

 

For some reason the syntax I tried first --> $first = key($hi1_array) , is working now. That is the returning the correct first key after the array is reset.

 

 

[teng84]

who's teng82? your making me old that makes me 2 yrs older!

[phpdolan]

who's teng82? your making me old that makes me 2 yrs older!

 

I thought that'd make you 2 years younger... You're kinda old to be programming???