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Parse error: parse error, unexpected T_ECHO in e:\domains\m\myhabs.co.uk\user\ht

rofl90

By rofl90
in PHP Coding Help

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rofl90 Advanced Member

rofl90

Posted
  • Author
Posted

heres whole code ftr

<?php

session_start();

$host = "mysql10.streamline.net";

$user = "x";

$pass = "x";

$db = "prowebdes1";



$ms = mysql_connect($host, $user, $pass);

if(!$ms) { echo "Error connecting to database.\n"; }

mysql_select_db($db);



if($_GET['login'] == "login") {

$user1_post = addslashes($_POST["username_post"]);

$pass1_post = addslashes($_POST["password_post"]);

$pass1_post = md5($pass1_post);

if($user1_post == "" or $pass1_post == "") { echo "<b>You Did Not Enter A Password</b>"; exit; }



list($user) = mysql_fetch_array(mysql_query("SELECT `username` FROM `staff` WHERE username='$user1_post'"));

list($pass) = mysql_fetch_array(mysql_query("SELECT `password` FROM `staff` WHERE password='$pass1_post'"));



if($user1_post == "$user" and $pass1_post == "$pass") {

$sql = mysql_query("SELECT * FROM `staff` WHERE username='$user' AND password='$pass'");

if(mysql_num_rows($sql)!= 1) { exit; }

$result = mysql_fetch_array($sql);



$_SESSION['session_username'] = $result['username'];

$_SESSION['session_level'] = $result['level'];

$_SESSION['session_ip'] = $_SERVER['REMOTE_ADDR'];



echo "<meta http-equiv=\"refresh\" content=\"0;url=main.php\">";

        exit;

} else { echo "<b>Your Username And Password Did Not Match</b>"; }

} else { ?>



<body bgcolor="#F45000" bgproperties="fixed" style="background-image: url('habboback.gif')">







<p align="center"> 

</p>



<center>

<div align="center">

<table width="329" height="3" style="border-collapse: collapse" cellpadding="0" cellspacing="0" id="table2">

<tr>

			<td width="330" height="11" align="center">

                </td>

		</tr>

<tr>

			<td align="center" width="400" background="hk_middle.gif" height="342">

			<form action="<?php echo "$PHP_SELF"; ?>?login=login" method="POST">

                  <font size="1"><br>

				 <img border="0" src="enterHH%20copy.gif" width="105" height="106"><br>

 </font><table border="0" id="table3" width="252" height="87">

<tr>

	<td>

	<p align="center"><b><font size="1" face="Verdana">Username:</font></b></td>

	<td><?

echo "<select size='1' name='username_post'>

<option selected>Choose Your Name</option>";

include('dbConfig.php');

$result = mysql_query("SELECT * FROM `staff`");

while($worked = mysql_fetch_array($result)) {

$username = $worked["username"];

echo "<option value=$username>$username</option>";

}

mysql_close(); ?>

</select></td>

	<td height="77" rowspan="4"> </td>

	</tr>

<tr>

	<td>

	<p align="center"><font size="1" face="Verdana"><b>Password:</b></font></td>

	<td>

	<p align="center"><font color="#FFFFFF" size="1" face="Verdana"> 

	<input type="password" name="password_post" size="26"></font></td>

</tr>

<tr>

	<td width="62"></td>

	<td width="172">

	 <input type='image' name='myclicker' src='hk_button.gif'></td>

	</tr>

	<tr>

	<td valign="top" colspan="2">

	<p align="center"></td>

	</tr>

</table>

<p align="center"><font face="Verdana" size="1" color="#FFFFFF">Warning Your IP Address is 
<?php
$ipa = getenv("REMOTE_ADDR")
echo "$ipa";
?>
Authorised FlyTropica staff only, we will do everything in our power to track down any 

unauthorised people. Abuse of this tool is strictly against the terms and 

conditions of service.</font></p>

</form></td>

</tr>

</table>



</div>













<p align="center"> </p>















<?php } ?>

rofl90 Advanced Member

rofl90

Posted
  • Author
Posted

Thanks but now it won't show - But it doesn't give errors!

 

;D

 

But it won't show for some reason it displays like this

Warning Your IP Address is Authorised

lol

 

Also how would I log the ip address in a file/table(mysql) of which I can check for unauthorised attempts?

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