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Hi, I am building a mini backend cms for a website and I want to be able to update the homepage welcome message by filling in a form, but I am gettin the following error:

 

ERROR: Duplicate entry '1' for key 1 INSERT INTO Welcome (Title, WelcomeText) VALUES ('Hello','Hello')

 

Can someone please have a look, thanks in advance.

 

Below is m code:

 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Add stock</title>
</head>

<body>
   <p><font face="Arial, Helvetica, sans-serif">
   <?
    $usr = "username";
    $pwd = "password";
    $db = "database";
    $host = "host";

    # connect to database
    $cid = mysql_connect($host,$usr,$pwd);
    if (!$cid) { echo("ERROR: " . mysql_error() . "\n");    }

?>
   </font></p>
   <TITLE></TITLE>
<P>Update welcome message    </P>

   <font face="Arial, Helvetica, sans-serif">
   <?
    # this is processed when the form is submitted
    # back on to this page (POST METHOD)
    if ($REQUEST_METHOD=="POST") {

        # double-up apostrophes
        $Title = str_replace("'","''",$Title);
        $WelcomeText = str_replace("'","''",$WelcomeText);

        # setup SQL statement
        $SQL = " INSERT INTO Welcome ";
        $SQL = $SQL . " (Title, WelcomeText) VALUES ";
        $SQL = $SQL . " ('$Title','$WelcomeText') ";


        #execute SQL statement
        $result = mysql_db_query($db,"$SQL",$cid);
	$ID=mysql_insert_id();


        # check for error
        if (!$result) { echo("ERROR: " . mysql_error() . "\n$SQL\n");    }

        echo ("<P>Welcome message updated</P>\n");

    }

?>
   </font>
<FORM NAME="fa" ACTION="index.php?page=welcomeMessage" METHOD="POST">
<TABLE>
<TR>
  <TD><font face="Arial, Helvetica, sans-serif"><B>Title: </B> </font></TD><TD><font face="Arial, Helvetica, sans-serif">
  <INPUT NAME="Title" TYPE="text" id="Title" value="<?php echo $Title; ?>" SIZE=40>
</font></TD></TR>
<TR>
  <TD height="96" VALIGN=TOP><font face="Arial, Helvetica, sans-serif"><B>Welcome message : </B> </font></TD><TD><p><font face="Arial, Helvetica, sans-serif"><textarea name="WelcomeText" cols=40 rows=5 id="WelcomeText"><?php echo $WelcomeText; ?></textarea>
</font></p>
    </TD>
</TR>
<TR>
  <TH COLSPAN=2><font face="Arial, Helvetica, sans-serif">
    <input name="submit" type="submit" value="Update message" />
  </font></TH>
</TR>
</TABLE>
<p align="center"> </p>
</FORM>


   <font face="Arial, Helvetica, sans-serif">
   <?    mysql_close($cid); ?>
   </font>
</BODY>
</HTML>

</body>
</html>

If the row already exists in the database, change your query to an UPDATE, and in your SQL statement "UPDATE Welcome WHERE Title ='title'"

Since it seems like your Title is your primary key, you cannot insert a new row with the same value as an already existant Primary ID.  If you need to change the title as well, then I would suggest adding another field to your database and set it as your unique id.

This thread is more than a year old. Please don't revive it unless you have something important to add.

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