Thundarfoot Posted January 31, 2008 Share Posted January 31, 2008 I am a noob working on my second script. I have 2 tables A & B Table A has 3 columns, the third column contains a number which represents the id of an entry in table B. I know how to query table a for its 3 columns and can show that output in a dynamic table. However this just shows the number in the thrid column.... I need to figure out how to take the number and fetch the correct entry from table b instead. Any help would be appreciated. Thank you for your time. Quote Link to comment Share on other sites More sharing options...
Cep Posted January 31, 2008 Share Posted January 31, 2008 You need a join in your sql statement, read this, http://en.wikipedia.org/wiki/Join_%28SQL%29 Quote Link to comment Share on other sites More sharing options...
Thundarfoot Posted January 31, 2008 Author Share Posted January 31, 2008 thank you for that link, it helps explain things a lot. But I am still having trouble making it work. I belive the join code I need to use is.. SELECT * FROM cubes LEFT OUTER JOIN mobs ON drops_from.id = mobs.id Should I be placing this in a query? I have tried to add the abovet o a query command but to no avail. here is the code I am working with now... Thank you in advance for any help you can give. mysql_select_db($database_LWC, $LWC); $query_Rs1_cubes = "SELECT * FROM cubes"; $Rs1_cubes = mysql_query($query_Rs1_cubes, $LWC) or die(mysql_error()); $row_Rs1_cubes = mysql_fetch_assoc($Rs1_cubes); $totalRows_Rs1_cubes = mysql_num_rows($Rs1_cubes); mysql_select_db($database_LWC, $LWC); $query_Rs2_Mobs = "SELECT * FROM mobs"; $Rs2_Mobs = mysql_query($query_Rs2_Mobs, $LWC) or die(mysql_error()); $row_Rs2_Mobs = mysql_fetch_assoc($Rs2_Mobs); $totalRows_Rs2_Mobs = mysql_num_rows($Rs2_Mobs); ?> <html> <body> <table border="1"> <tr> <td>id</td> <td>Cube Type</td> <td>Drops From</td> </tr> <?php do { ?> <tr> <td><?php echo $row_Rs1_cubes['id']; ?></td> <td><?php echo $row_Rs1_cubes['Cube Type']; ?></td> <td><?php echo $row_Rs1_cubes['Drops From']; ?></td> </tr> <?php } while ($row_Rs1_cubes = mysql_fetch_assoc($Rs1_cubes)); ?> </table> <p> </p> </body> </html> <?php mysql_free_result($Rs1_cubes); mysql_free_result($Rs2_Mobs); ?> Quote Link to comment Share on other sites More sharing options...
revraz Posted January 31, 2008 Share Posted January 31, 2008 SELECT * FROM cubes JOIN mobs ON (cubes.id = mobs.id) Depending on what the fieldname is in cubes that you want to link mobs with. Quote Link to comment Share on other sites More sharing options...
Thundarfoot Posted January 31, 2008 Author Share Posted January 31, 2008 Thank you! Quote Link to comment Share on other sites More sharing options...
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