[SOLVED] passing a function as an argument of a function

[resago]

I'm having a brain fart and search has failed me.

 

can someone give a quick example?

 

like:

function foo ($funk){

do stuff

call function as represented by $funk

}

 

foo (phpinfo());

 

thanks!

[haku]

Not sure what your question is here.

[PHP Monkeh]

Not entirely sure if this is the best way, but this worked for me:

 

<?php

function foo($funk) {

   eval($funk());

}

foo("phpinfo");

?>

[Barand]

try

<?php 
$funk = 'phpinfo';

function foo ($f)
{
     $f();
}

foo ($funk);
?>

[PHP Monkeh]

Trust me to over-complicate things and use eval()   Barand makes me feel stupid at times!

[resago]

try

<?php 
$funk = 'phpinfo';

function foo ($f)
{
     $f();
}

foo ($funk);
?>

 

well duh...

thanks!