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I know this code is wrong, but it has the correct idea in what i want it to do.

Rather than printing 'Upload Failed' or 'Uploaded Successfully' for each file type in the array, what would be the correct way to print whether it failed or not (without using die). Am i using the wrong loop?

 

<?php
function checkFileType($filename, $filetype)
{
$filetypes[0] = 'image/jpeg';
$filetypes[1] = 'image/jpg';
$filetypes[2] = 'image/gif';
$filetypes[3] = 'image/png';
$filetypes[4] = 'image/bmp';
$filetypes[5] = 'image/tif';
$filetypes[6] = 'image/tiff';

for($filetypes as $files) 
{
	if($filetype != $files)
	{
		echo 'Upload Failed';
	}
	else
	{
		echo 'Uploaded Successfully';
	}
}
}
?>

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https://forums.phpfreaks.com/topic/89816-solved-file-array/
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why dont you use in_array to check for file types?

 

 

<?php

$mixed_needle = $_FILES['file']['type']; // File
$array_haystack = array('image/png','image/pjpeg'); // File Types 

if(!in_array($mixed_needle,$array_haystack)){ // not the correct file type 
}else
{ 
// Is good 
}
?>

 

 

 

 

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https://forums.phpfreaks.com/topic/89816-solved-file-array/#findComment-460271
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