[SOLVED] unix timestamp

[phorcon3]

<?php

$timestamp = time();

?>

 

and let's say this equals to 1202482743

 

<?php

echo date('F j, Y @ g:i A', 1202482743);

?>

 

which then equals to February 8, 2008 @ 3:59 PM

 

but how could i transform the unix timestamp (1202482743) so it would output February 8, 2008 @ 12:00 AM ..so it's the beginning of the day?

 

i can only think of a really stupid way to do it, and that would be it

 

<?php

$timestamp = time();

$month = date('n', $timestamp);
$day = date('j', $timestamp);
$year = date('Y', $timestamp);

echo date('F j, Y @ g:i A', mktime(0,0,0,$month,$day,$year));

?>

 

can anyone else think of a better way to do it?

[aschk]

You need to round it to something like 1202480000

note: this is a guess method that might work.

[aschk]

What's wrong with

echo date('F j, Y', 1202482743)." @ 12:00 AM";

[phorcon3]

because i have to compare it to something.. its gotta be between a certain timeframe

[PFMaBiSmAd]

mktime(0,0,0,$month,$day,$year) is actually the best available method.

 

The strtotime() function can probably do it, but there is a general lack of documentation about what special operators it has available.

[phorcon3]

oh, alright ..thanks

[laffin]

simple

convert timestamp to date string without time portion so it's a date, convert this into a timestamp. (this can be done initially as well, so timestamp never has the time information).

 

<?php
$timestamp = 1202482743;
$startofday = strtotime(date("Y-m-d",$timestamp));
echo date('F j, Y @ g:i A',$startofday);

?>